F(x)=2x^2-5 g(x)=5x+7
1 answer:
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Simple...
you have:
and
To solve for....
Multiply to remove the denominator-->>
n=12*3
n=36
Then-->>>
Do the same thing-->>
n=-12*3
n=-36
Thus, your answer.
you have:
and
To solve for....
Multiply to remove the denominator-->>
n=12*3
n=36
Then-->>>
Do the same thing-->>
n=-12*3
n=-36
Thus, your answer.
A perfect cube is a natural number in the form
therefore
and also you can define it as any natural number who's third root is also a natural number for examble
![\sqrt[3]{1000} = 10](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B1000%7D%20%20%3D%2010)
so you can say that the tenth perfect cube is 1000
therefore
and also you can define it as any natural number who's third root is also a natural number for examble
so you can say that the tenth perfect cube is 1000