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Flura [38]
2 years ago
10

Arrange the following number in descending order 0,9; 0,009; 0,09; 0,0009 ;9,09​

Mathematics
1 answer:
VLD [36.1K]2 years ago
8 0

Answer:

9.09 , 0.9 , 0.09 , 0.009 , 0.0009

Explanation:

The more places behind a decimal point a number is, the smaller it is

Hope this helped you! :)

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Evaluate the expression \dfrac{7^2}{x^2-2} x 2 −2 7 2 ​ start fraction, 7, squared, divided by, x, squared, minus, 2, end fracti
sertanlavr [38]

Answer:

7

Step-by-step explanation:

We want to evaluate the fraction below for x = 3. We will put the value of x to be 3:

\dfrac{7^2}{x^2-2}\\\\= \dfrac{7^2}{3^2-2}\\\\= \dfrac{49}{9-2}\\\\= \dfrac{49}{7} = 7

The answer is 7.

3 0
3 years ago
rachel types 162 words in 3 minutes rachel types at a constant rate. how many words does rachel type per minute
Rainbow [258]
Divide the number of words she types (162) by 3 mins = 54 words in 1 minute
8 0
2 years ago
If f(x) = 1 – x2 + x3, then f(-1) =
Monica [59]

Answer:

Step-by-step explanation:

f(-1)= 1 - (-1)^2 + (-1)^3 = 1 - 1 - 1 = 0 - 1 = -1

4 0
2 years ago
Solve the system of linear equations by elimination.<br><br><br>3x - 2y = 4<br>6x- 2y = -2​
Nikitich [7]

Answer:

the value of x is (-2) and y is (-5)

7 0
3 years ago
PLEASE HELP.
OverLord2011 [107]

Answer:

Explicit formula for

1) a_n=17-3(n-1)

2) a_n=(\frac{1}{2} )^{n-1}\cdot 20

Step-by-step explanation:

W have to find the first few terms of the given sequence and then find an explicit equation

Explicit formula = f(n) + d(n-1) , where,

f(n) is first term,

d is common difference,

n-1 is one term less than the term number.

1)

Given : a_1=17\\\\a_{n+1}=a_n-3

\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\

Thus, we obtained an explicit formula,

a_n=17-3(n-1)

2)

Given : a_1=20\\\\a_{n+1}=\frac{1}{2} \cdot a_n

\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\

Thus, we obtained an explicit formula,

a_n=17-3(n-1)

\text{We put n =1, we get,}\\\\\\a_2=\frac{1}{2} \cdot a_1=\frac{1}{2} \cdot 20=10=(\frac{1}{2} )^{2-1}\cdot 20\\\\\\\text{We put n =3, we get,}\\\\\\a_4=\frac{1}{2} \cdot a_3=\frac{1}{2} \cdot 5=\frac{5}{2}=(\frac{1}{2} )^{4-1}\cdot 20\\\\\\

Thus, we obtained an explicit formula,

a_n=(\frac{1}{2} )^{n-1}\cdot 20

8 0
3 years ago
Read 2 more answers
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