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olga_2 [115]
2 years ago
12

Answer quickly give brainiest answer

Mathematics
2 answers:
tatyana61 [14]2 years ago
8 0
Yes I checked it his answer is valid
storchak [24]2 years ago
3 0

Answer:

A. 6

B. 3 and 3

Step-by-step explanation:

A) 8x3/4

B) since the area is three and you have to spit the triangle down the middle...

You draw a line diagonally from the top right corner to the bottom left corner and the area would be 3 and 3 because 6 in half is 3

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A ball bearing has mass 0.44 pounds. 1 kg = 2.2 pounds. <br>​
torisob [31]

Answer:

  (i) 0.2 kg

  (ii) kg/cm³

  (b) 2.29 kg

Step-by-step explanation:

This problem gives you relations between units, and the formulas for density and mass. It is asking you to make use of these relations in various mass and density calculations.

<h3>(a)(i)</h3>

The relationship between kg and pounds can be used to write a units conversion multiplier. It will have numerator equal to denominator, but will have units such that multiplying by it will give the units you want.

  0.44 pounds × multiplier = __ kg

  0.44 pounds × (1 kg)/(2.2 pounds) = (0.44/2.2)(1 kg)

  0.44 pounds = 0.2 kg

__

<h3>(a)(ii)</h3>

The formula can be used to find the units of interest:

  Density = mass/volume

  units of density = (units of mass)/(units of volume)

  units of density = kg/cm³

__

<h3>(b)</h3>

Using the given formula with the given value of L, we find the volume to be ...

  V = 4(1.40 cm)(3 -1.40 cm)² = 14.336 cm³

Then the mass is ...

  mass = volume × density

  mass = (14.336 cm³)×(0.160 kg)/(1 cm³) = 2.29376 kg

The mass is about 2.29 kg.

_____

<em>Additional comment</em>

Often you will see density in terms of kg/m³ or g/cm³. Water has a density of about 1 g/cm³ or 1000 kg/m³. The most dense non-radioactive element in the periodic table is osmium, with a density of about 22.6 g/cm³, or 0.0226 kg/cm³. The material in part (b) of this problem has a density about 7 times that, so is clearly not from Earth.

7 0
2 years ago
What is the distance between P(12, 4) and Q(-8, 2)
abruzzese [7]

\huge{\boxed{2 \sqrt{101}}}

The distance formula is \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, where (x_1, y_1) and (x_2, y_2) are the points.

Substitute in the points. \sqrt{(2-4)^2+(-8-12)^2}

Subtract. \sqrt{(-2)^2+(-20)^2}

Solve the exponents. \sqrt{4+400}

Add. \sqrt{404}

Now, we can simplify this square root just a little bit. 404 has a square factor of 4. \sqrt{404}=\sqrt{4}*\sqrt{101}

The square root of 4 equals 2. \boxed{2 \sqrt{101}}

6 0
3 years ago
Read 2 more answers
As you can see, I already answered part A. That part is easy, like kindergarten level. But I don't remember learning how to do p
drek231 [11]

Answer:

Length: 10 units.

Width:6 units

Step-by-step explanation:

Part a has 1 unit =40 yards. When we have 1 unit = 20 yards, we have divided the original numbers, 40, in half, getting 20. That means that we need to double the original amount of units, like you see above.

3 0
3 years ago
Read 2 more answers
Seven times a number n and 4
WARRIOR [948]

anything above 28

Step-by-step explanation:

Seven times 4 is 28, times any number is anything 28 and above

5 0
3 years ago
Read 2 more answers
The perimeter of a rectangular swimming pool is 160 feet . The length of the swimming pool is four times its width. Find the dim
Murrr4er [49]
Formula for Perimeter of Rectangle:

P = 2(L + W)

Plug in 160:

160 = 2(L + W)

L = 4W
So we can plug in '4W' for 'L' in the first equation.
<span>160 = 2(L + W)

160 = 2(4W + W)

Combine like terms:

160 = 2(5W)

160 = 10W

Divide 10 to both sides:

W = 16

Now we can plug this back into any of the two equations to find the length.

L = 4W

L = 4(16)

L = 64

So the width is 16, and the length is 64.</span>
6 0
3 years ago
Read 2 more answers
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