We will start off working on the right hand side.
<span>cot x - tan x </span>
<span>= [cos x / sin x] - [sin x / cos x] </span>
<span>= [(cos x)^ 2 - (sin x)^2] / [sin x cos x] </span>
<span>This is where it gets a bit tougher if you do not have your formula list with you. </span>
<span>(cos x)^ 2 - (sin x)^2 = cos(2x) </span>
<span>sin 2x = 2 sin x cos x </span>
<span>Note that by arranging the second formula, we will have sin x cos x = (1/2) sin 2x </span>
<span>Hence, we will get: </span>
<span>[(cos x)^ 2 - (sin x)^2] / [sin x cos x] </span>
<span>= [cos 2x] / (1/2)[sin 2x] </span>
<span>= 2[cos 2x] / [sin 2x] </span>
<span>= 2cot 2x </span>
I think those are coordinates of points, (-5,8) and (-2,8)
so you just need to use distance formula ((8-8)^2+(-2+5)^2)=0+9=9
square root 9=3
Answer:
y = -3x + 7
Step-by-step explanation:
The equation of a line
y = mx + c
y - intercept point y
m - slope of the line
x - intercept point x
c - intercept point of the line
Step 1: find the slope
m = y2 - y1 / x2 - x1
Given two points
( 1 , 4) ( 2 , 1)
x1 = 1
y1 = 4
x2 = 2
y2 = 1
insert the values
m = 1 - 4 / 2 - 1
m = -3/1
m = -3
y = -3x + c
Step 2: substitute any of the two points given into the equation of a line
y = -3x + c
( 1 ,4)
x = 1
y = 4
4 = -3(1) + c
4 = -3 + c
4 + 3 = c
c = 7
Step 3: sub c into the equation
y = -3x + 7
The equation of the line is
y = -3x + 7
Start with an equation summing all the angles in this triangle:
180 = <M + <N + <P
we are given <M and <N but not <P. But, since MN=NP, the angle <P is the same as the angle <M (isosceles, make a drawing to see). So
180 = 2<M + <N
180 = 2(3x+1) + x-11
180 = 7x - 9
x = 27
<P = 3*27+1 = 82 degrees
The answer isss..................... 69
