The area of the top of a desk which is shown and the dimensions of the top is 5 feet and 2 feet, is 10 squared feet.
<h3>What is the area of a rectangle?</h3>
Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

Here, (a)is the length of rectangle and (b) is the width of the rectangle
A drawing of the top of a desk is shown.
The image of drawing ins not given in the problem. Here, the length of the desk is 5 feet and the width of the desk is 2 feet according to the data.

Put the values in the above written formula as,

Thus, the area of the top of a desk which is shown and the dimensions of the top is 5 feet and 2 feet, is 10 squared feet.
Learn more about the area of rectangle here;
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WEW can use a simple equation to solve this
Let x be the number of kilometers she hiked in the morning . Then
x - 0.25x = 6 (Note 0.25 = 25 %)
0.75x = 6
x = 6 / 0.75 = 8 kilometers answer
Answer:
x=−5
Step-by-step explanation:
x+12=7
Step 1: Subtract 12 from both sides.
x+12−12=7−12
x=−5
Answer:
Step-by-step explanation:
For this case we are interested on the region shaded on the figure attached.
And we can find the volume with the method of rings.
The area on this case is given by:
![A(x) = \pi [f(x)]^2 = \pi r^2 = \pi [3x]^2 = 9\pi x^2](https://tex.z-dn.net/?f=%20A%28x%29%20%3D%20%5Cpi%20%5Bf%28x%29%5D%5E2%20%3D%20%5Cpi%20r%5E2%20%3D%20%5Cpi%20%5B3x%5D%5E2%20%3D%209%5Cpi%20x%5E2)
And the volume is given by the following formula:

For our case our limits are x=0 and x=2 so we have this:

And if we solve the integral we got this:
![V= \pi [\frac{x^3}{3}]\Big|_0^{2}](https://tex.z-dn.net/?f=%20V%3D%20%5Cpi%20%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5D%5CBig%7C_0%5E%7B2%7D)
And after evaluate we got this:
![V=\pi [(\frac{8}{3} )-(\frac{0}{3} )]](https://tex.z-dn.net/?f=%20V%3D%5Cpi%20%5B%28%5Cfrac%7B8%7D%7B3%7D%20%29-%28%5Cfrac%7B0%7D%7B3%7D%20%29%5D)
Answer:
B
Step-by-step explanation:
that seems like the best option to me