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SIZIF [17.4K]
2 years ago
6

Solve the Quadratics:

Mathematics
1 answer:
klasskru [66]2 years ago
6 0

Answer:

Step-by-step explanation:

1 ) k²-8k = 0

k(k-8)=0

k = 0 or k=8

2) a²+5a=0

a(a+5) = 0

a=0 or a  = - 5

3 ) 6n²+5n-25=0

delta = b²-4ac      b =5 and a = 6   and   c= - 25

delta = 5²-4(6)(-25) = 625 = 25²

n 1 = (-5+25)/12 = 20/12 = 5/3

n 2 = (-5-25)/12 = -  30/12  = -5/2

same method for 4) and 5)

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Answer:

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What does a=? b=? Angle B=?
Kobotan [32]

Answer:

If you were solving the right triangle, it would be:

m∠A = 46°

m∠B = 44°

m∠C = 90°

AB = 32

BC ≈ 23

AC ≈ 24

Step-by-step explanation:

To solve this right triangle, you can use trigonometric ratios to solve for the sides. To find the angle measures:

m∠A = 46° (given)

m∠B = x

m∠C = 90° (given)

180 - (46 + 90) = x

180 - 136 = x

44 = x

m∠B = 44°

To find the side measures, you can use tangent, sine, cosine, and the Pythagorean Theorem.

Recall that:

tangent = opposite side/adjacent side

sine = opposite side/hypotenuse

cosine = adjacent side/hypotenuse

So:

sin46 = BC/32

BC = 32 (sin46)

BC ≈ 23

tan46 = BC/AC

AC = BC/tan46

AC = (23.01887361...) (tan46)

AC ≈ 24

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2 years ago
Whats the ninth term of 25 20 15 10 5
Kaylis [27]

Given:

The sequence is 25, 20, 15, 10, 5.

To find:

The ninth term of the given sequence.

Solution:

We have,

25, 20, 15, 10, 5

It is an AP because the difference between two consecutive terms are same.

Here,

First term (a) = 25

Common difference (d) = 20-25

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The nth terms of an AP is

a_n=a+(n-1)d

Where, a is the first term and d is the common difference.

Putting a=25, n=9 and d=-5 to get the 9th term.

a_9=25+(9-1)(-5)

a_9=25+(8)(-5)

a_9=25-40

a_9=-15

Therefore, the ninth term of the given sequence is -15.

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2 years ago
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