Answer:
3
Explanation:
From the question:
Barium phosphate reacts with sulfuric acid to form barium sulfate and phosphoric acid.
The equation for the above reaction can be written as follow:
Ba3(PO4)2 + H2SO4 —> BaSO4 + H3PO4
Now, let us balance the equation in order to obtain the coefficient of H2SO4. This is illustrated below below:
Ba3(PO4)2 + H2SO4 —> BaSO4 + H3PO4
There are 3 atoms of Ba on the left side of the equation and 1 atom on the right side. It can be balance by putting 3 in front of BaSO4 as shown below:
Ba3(PO4)2 + H2SO4 —> 3BaSO4 + H3PO4
There are 3 atoms of SO4 on the right side and 1 atom on the left side. It can be balance by putting 3 in front of H2SO4 as shown below:
Ba3(PO4)2 + 3H2SO4 —> 3BaSO4 + H3PO4
Now, we can see that there 6 atoms of H on the left side and 3 atoms on the right side. It can be balance by putting 2 in front of H3PO4 as shown below:
Ba3(PO4)2 + 3H2SO4 —> 3BaSO4 + 2H3PO4
Now the equation is balanced.
The coefficient of sulphuric acid (H2SO4) is 3
