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2 years ago

Latanya was asked to determine if (375,4) lies on the circle with radius 7 centered at (0.-2). what is her error?

Mathematics

1 answer:

Vilka [71]2 years ago

6 0

The point (3/5,4) would lie on the circle if it makes the equation of the circle to be true

Latansha's equation of the circle is wrong

<h3>How to determine her error?</h3>

The given parameters are:

Center = (a,b) = (0,-2)

Radius, r = 7

The equation of a circle is:

$(x - a)^2 + (y - b)^2 = 0$

This gives

$(x - 0)^2 + (y + 2)^2 = 0$

Rewrite as:

$x^2 + (y + 2)^2 = 0$

In Latanya's first step, we have:

$x^2 + (y - 2)^2 = 0$

By comparing her first step with x^2 + (y + 2)^2 = 0, we can see that her equation is wrong

Hence, Latansha's error is that she determine the equation of the circle, wrongly.

Read more about circle equations at:

brainly.com/question/1559324

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Lim t^4 - 6 / 2t^2 - 3t + 7

Harman [31]

I think you meant to say

$\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}$

(as opposed to x approaching 2)

Since both the numerator and denominator are continuous at t = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}$

Because these expressions are continuous at t = 2, we can compute the limits by evaluating the limands directly at 2:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}$

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3 years ago

A number line is divided into fifths. How many equal segments are there between the point at zero and the point 4/5?

ella [17]

Answer:

Step-by-step explanation:

A little confused by the question but is it just

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3 years ago

Maria is recording the percentages she earned on each quiz in her math class. Here are her results for the last 7 quizzes.

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3 years ago

Triangle A B C is cut by line segment S T. Line segment S T goes from side A B to side C B. Lines S T and A C are parallel. The

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Answer:

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$\dfrac{SA}{SB}=\dfrac{CT}{BT}$