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2 years ago

There are 3 adults for every 5 children at the party. How many adults are there if there are 35 children?

Mathematics

2 answers:

inysia [295]2 years ago

8 0

Answer:

105 maybe I just multipled 35 by 3

Savatey [412]2 years ago

3 0

Answer:

your answer would be 21 adults.

Step-by-step explanation:

first, see how many times 5 goes into 35, next multiply 3 by that many times, you have your answer! 21

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The number of pens sold at the school bookstore on Monday, p, increased 45% on Tuesday. The expression p+0.45p represents the nu

butalik [34]

Answer:

p + (45/100) p or 1.45 p

Step-by-step explanation:

8 0

2 years ago

Norman makes $15 commission for selling $200 in merchandise. he makes $37.50 commission for selling $500 in merchandise. assumin

vladimir2022 [97]

So he needs to sell $2,000 in merchandise.

<h3>what is the total value of merchandise he needs to sell?</h3>

We can assume that we have a proportional relation:

y = k*x

Where y is the commission and x is what Norman sells, then:

$15 = k*$200

k = $200/$15 = 0.075

$37.50 = k*$500

k = $500/$37.50 = 0.075

Then the relation is:

y = 0.075*x

If he wants a commission of $150, then:

$150 = 0.075*x

$150/0.075 = x = $2,000

So he needs to sell $2,000 in merchandise.

If you want to learn more about proportional relationships:

brainly.com/question/12242745

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3 0

1 year ago

In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of

In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

A line segment joining the mid-points of two sides in a triangle is parallel to the third side and equal to half its length

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = $\frac{1}{2}$ MN

∵ JL = 11 units

∴ 11 = $\frac{1}{2}$ MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = $\frac{1}{2}$ MO

∵ KL = 13 units

∴ 13 = $\frac{1}{2}$ MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = $\frac{1}{2}$ ON

∵ ON =20 units

∴ JK = $\frac{1}{2}$ (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0

3 years ago

What is the vertex of the quadratic function f(x)=(x-6)(x+2)

Neporo4naja [7]

Answer: ( 2, -6 )

Step-by-step explanation:

rewrite y= (x-6)(x+2) in the form y=ax^2+bx+c

Y=(x-6)(x+2)

(x-6)(x+2): x^2-4x-12

y=x^2-4x-12

the parabola params are :

a=1, b= -4, c=-12

x^v=-(-4)/ 2*1

x^v=2

y^v=-16

5 0

2 years ago

College Math!!! I did the first half of the question, I just need the bottom half of it.

ella [17]

Answer:

-49

Step-by-step explanation:

$\int _{-5}^{-2}\:\left(8\:w\left(r\right)-3\right)dr$ = $\int _{-5}^{-2}\:8\:w\left(r\right)dr$ -3 (-2 -(-5)) = $8 \int _{-5}^{-2}\:\:w\left(r\right)dr$ -9 =8(-5) -9 = -49

7 0

2 years ago