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ICE Princess25 [194]
2 years ago
15

Match the simplified version of the number given. Note: You do not need to find the opposite for the number, just the simplified

number. Use the following clues:
The opposite of a positive number is a negative number and vice versa.
The opposite of the opposite of a positive number is a positive number.
The opposite of the opposite of a negative number is a negative number.
1. -(-75)
-20
2. -(87)
-75
3. -(20)
75
4. -(-20)
-12
5. -(12)
12
6. -(-12)
20
7. -(75)
-87
8. -(-(87)
87
Mathematics
1 answer:
mart [117]2 years ago
8 0

The matching forms of the numbers are as represented below upon evaluation;

  1. -(-75) = 75
  2. -(87) = -87
  3. -(20) = -20
  4. -(-20) = 20
  5. -(12) = -12
  6. -(-12) = 12
  7. -(75) = -75
  8. -(-87) = 87

<h3>Opening up parenthesis</h3>

The given numbers can be simplified by opening up the parenthesis as indicated above in which case,

  • The product of 2 negatives equals a positive sign

  • The product of ,a negative and positive equals negative.

Read more on parenthesis;

brainly.com/question/25935638

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A research firm tests the miles-per-gallon characteristics of three brands of gasoline. Because of different gasoline performanc
Anni [7]

Answer:

A.) At α = 0.05, is there a significant difference in the mean miles-per-gallon characteristics of the three brands of gasoline.

B.)<u><em>The advantage of attempting to remove the block effect is</em></u>

The completely randomized designs does not prove that H0 is incorrect only that it cannot be rejected.

Step-by-step explanation:

<em><u /></em>

<em><u>Using Two-way ANOVA method</u></em>

Given problem

<em><u>Observation              I          II       III          Row total (xr)</u></em>

A                              18 21 20            59

B                            24 26 27             77

C                            30 29 34             93

D                            22 25 24            71

<u>E                            20 23 24           63                      </u>

Col total (xc)             114 124 129        367

∑x²=9233→(A)

∑x²c/r

=1/5(114²+124²+129²)

=1/5(12996+15376+16641)

=1/5(45013)

=9002.6→(B)

∑x²r/c

=1/3(59²+77²+93²+71²+67²)

=1/3(3481+5929+8649+5041+4489)

=1/3(27589)

=9196.3333→(C)

(∑x)²/n

=(367)²/15

=134689/15

=8979.2667→(D)

Sum of squares total

SST=∑x²-(∑x)²/n

=(A)-(D)

=9233-8979.2667

=253.7333

Sum of squares between rows

SSR=∑x²r/c-(∑x)²/n

=(C)-(D)

=9196.3333-8979.2667

=217.0667

Sum of squares between columns

SSC=∑x²c/r-(∑x)²/n

=(B)-(D)

=9002.6-8979.2667

=23.3333

Sum of squares Error (residual)

SSE=SST-SSR-SSC

=253.7333-217.0667-23.3333

=13.3333

<u>ANOVA table</u>

Source                 Sums         Degrees      Mean Squares

of Variation       of Squares   of freedom

<u>                               SS                 DF              MS       F p-value</u>

B/ w     SSR=217.0667              4 MSR=54.2667    32.56 0.0001

rows

B/w     SSC=23.3333         c-1=2 MSC=11.6667        7 0.01

columns

<u>Error (residual)SSE=13.3333 (r-1)(c-1)=8 MSE=1.6667                  </u>

<u>Total SST=253.7333 rc-1=14                                                        </u>

Conclusion:

<u> 1. F for between Rows</u>

The critical region for F(4,8) at 0.05 level of significance=3.8379

The calculated F for Rows=32.56>3.8379

Therefore H0 is rejected

<u>2. F for between Columns</u>

The critical region for F(2,8) at 0.05 level of significance=4.459

We see that the calculated F for Colums=7>4.459

therefore H0 is rejected,and concluded that there is significant differentiating between columns

<u><em>Part B:</em></u>

To analyze the data for completely  randomized designs click on anova two factor without replication  in the data analysis dialog box of the excel spreadsheet.

The following table is obtained

Source DF             Sum                  Mean           F Statistic

<u>                 (df1,df2)    of Square (SS) Square (MS)                    P-value</u>

Factor A       1 1496.5444 1496.5444 769.6514          0.001297

Rows

Factor B -     2 19.4444           9.7222               5                  0.1667

Columns

Interaction

AB               2    3.8889   1.9444        0.1013         0.9045

<u> Error     12   230.4            19.2                                           </u>

<u>Total 17 1750.2778 102.9575                                                         </u>

<u />

<u>Factor - A- Rows</u>

Since p-value < α, H0 is rejected.

<u>Factor - B- Columns</u>

Since p-value > α, H0 can not be rejected.

The averages of all groups assume to be equal.

<u>Interaction AB</u>

Since p-value > α, H0 can not be rejected.

<u><em>The advantage of attempting to remove the block effect is</em></u>

The completely randomized designs does not prove that H0 is incorrect only that it cannot be rejected.

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Graph x+y=6 4x+y=20<br><br>I NEED HELP <br>​
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Answer:Hi is this a simultaneous equation,

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3 years ago
Translate the algebraic expression in written language: 9 - x²​
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Answer:

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8 0
3 years ago
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
Rachel reads 1/5 of the pages of a book plus 12 pages on the first day.
kkurt [141]

Answer:

Let's say that the whole book have 5a pages.

First day: a + 12

Second day: (4a)1/4+15= a + 15

Third day: (1/3)[ 4a - (a+15)] +18= a + 13

Forth day: 70

So we get this:

(a + 12) + (a + 15) + (a + 13) + 70 = 5a

a + 12 + a + 15 + a + 13 + 70 = 5a

3a + 110 = 5a

3a - 5a = -110

-2a = -110

a = 55

5a = 5(55) = 275

So the total pages are in the book is:

275 pages

6 0
3 years ago
Read 2 more answers
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