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nalin [4]
2 years ago
15

PLEASE HELP WILL MARK BRAINLIEST!!

Mathematics
1 answer:
ipn [44]2 years ago
7 0

In the figure, PA and PB are tangents from point P. <u>AB is a chord</u> of the circle.

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Draw graphs of the following lines: The line through the origin having a slope of 1/4
KengaRu [80]
I think its 1 on the graph correct me if im wrong
4 0
3 years ago
The playground of a school has areas fixed for various activities. One-fifth of the playground is used for students to sit and r
sertanlavr [38]

Answer:

2/3* 4/5 = 8/15

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please have a look at the attached file below.

Given:

  • One-fifth (1/5)  of the playground is used for students to sit and read
  • 2/3 is used for playing soccer
  • The rest of the playground is used for playing basketball

So assume that the the playground is divided into 5 equal part

=> 1 part is used for students to sit and read or (1/5)

=>  the remaining equal part is 4  or (4/5)

Because 2/3 of the remaining part is used for playing soccer

=> the equation represents the part of the playground used for soccer is:

2/3 of 4/5

= 2/3* 4/5

= 8/15

8 0
3 years ago
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test.
asambeis [7]
Building time :
4c + 6a < = 120

testing time :
4c + 4a < = 100

20 child bikes and 6 adult bikes...c = 20 and a = 6
sub into both equations
4c + 6a < = 120
4(20) + 6(6) < = 120
80 + 36 < = 120
116 < = 120 (correct)

4c + 4a < = 100
4(20) + 4(6) < = 100
80 + 24 < = 100
104 < = 100 (incorrect)

ur answer : No, because the bike order does not meet the restrictions of 4c + 6a < = 120 and 4c + 4a < = 100
6 0
3 years ago
A number cube has faces labeled 1-6. What is the probability of rolling a 4 on the number cube and landing on a 2 on this spinne
Lunna [17]
I think its A once again i THINK its A sorry if im wrong 
 
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6 0
3 years ago
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