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Wittaler [7]
2 years ago
9

Determine the equation of the circle graphed below. (help fast ez pts)

Mathematics
1 answer:
ikadub [295]2 years ago
4 0

Answer:

(x + 4)² + (y + 7)² = 4

Step-by-step explanation:

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I only need #16 this Test/homework is hard. Help
Amiraneli [1.4K]

Answer:

d

Step-by-step explanation:

8 0
2 years ago
Please help me this is due today
Serjik [45]

Answer:

1. 15 (A)

2. 12 (G)

Step-by-step explanation:

1.  We can make an equation out of this...

    3x+3=48

    x is the age of Geoff which is what we are trying to find out

   

    We have to add 3 to both sides of the equation

    3x+3=48

         -3   -3

     ________

    we end up with 3x=45

     we then have to divide 3 by both sides because its the opposite of                

     multipling

    3x=45

    _____

         3

    we get x=15

2.   We can write a problem statement  

      (2 x 9)-6=?

       multiply 2 and 9 <u>FIRST</u>

     

       18-6=?

       your answer is 12

      Your Welcome! Have a great rest of your day! :)

 

       

     

7 0
2 years ago
Write out the form of the partial fraction decomposition of the function. Do not determine the numerical values of the coefficie
Dvinal [7]
For part (a), you have

\dfrac x{x^2+x-6}=\dfrac x{(x+3)(x-2)}=\dfrac a{x+3}+\dfrac b{x-2}
x=a(x-2)+b(x+3)

If x=2, then 2=b(2-3)\implies b=-2.

If x=-3, then -3=a(-3-2)\implies a=\dfrac35.

So,

\dfrac x{x^2+x-6}=\dfrac 3{5(x+3)}-\dfrac 2{x-2}

For part (b), since the degrees of the numerator and denominator are the same, you first need to find the quotient and remainder upon division.

\dfrac{x^2}{x^2+x+2}=\dfrac{x^2+x+2-x-2}{x^2+x+2}=1-\dfrac{x+2}{x^2+x+2}

In the remainder term, the denominator x^2+x+2 can't be factorized into linear components with real coefficients, since the discriminant is negative (1-4\times1\times2=-7). However, you can still factorized over the complex numbers, so a partial fraction decomposition in terms of complexes does exist.

x^2+x+2=0\implies x=-\dfrac12\pm\dfrac{\sqrt7}2i
\implies x^2+x+2=\left(x-\left(-\dfrac12+\dfrac{\sqrt7}2i\right)\right)\left(x-\left(-\dfrac12-\dfrac{\sqrt7}2i\right)\right)
\implies x^2+x+2=\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)

Then you have

\dfrac{x+2}{x^2+x+2}=\dfrac a{x+\dfrac12-\dfrac{\sqrt7}2i}+\dfrac b{x+\dfrac12+\dfrac{\sqrt7}2i}
x+2=a\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)+b\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)

When x=-\dfrac12-\dfrac{\sqrt7}2i, you have

-\dfrac12-\dfrac{\sqrt7}2i+2=b\left(-\dfrac12-\dfrac{\sqrt7}2i+\dfrac12-\dfrac{\sqrt7}2i\right)
\dfrac32-\dfrac{\sqrt7}2i=-\sqrt7ib
b=\dfrac12+\dfrac3{2\sqrt7}i=\dfrac1{14}(7+3\sqrt7i)

When x=-\dfrac12+\dfrac{\sqrt7}2i, you have

-\dfrac12+\dfrac{\sqrt7}2i+2=a\left(-\dfrac12+\dfrac{\sqrt7}2i+\dfrac12+\dfrac{\sqrt7}2i\right)
\dfrac32+\dfrac{\sqrt7}2i=\sqrt7ia
a=\dfrac12-\dfrac3{2\sqrt7}i=\dfrac1{14}(7-3\sqrt7i)

So, you could write

\dfrac{x^2}{x^2+x+2}=1-\dfrac{x+2}{x^2+x+2}=1-\dfrac {7-3\sqrt7i}{14\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)}-\dfrac {7+3\sqrt7i}{14\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)}

but that may or may not be considered acceptable by that webpage.
5 0
3 years ago
Read 2 more answers
Which table represents a
Andrej [43]

Answer:

H.

Step-by-step explanation:

H is not a function because its x-values occur more than once.

HTH :)

5 0
2 years ago
WILL GIVE MEDAL!! A flight of stairs is supported by two columns as shown. What is the distance from the base of the stairs to t
adell [148]
I saw the image. It formed 2 right triangles. 1 small and 1 big.
small triangle has a long leg of 4 feet and hypotenuse of 6 feet.
big triangle has a long leg of (x) and hypotenuse of 6 + 12 ft.

proportion:

4/6 = x / 18
4 * 18 = 6x
72 = 6x
72/6  = x
12 = x

The distance from the base of the stairs to the tallest column is 12 feet.

6 0
3 years ago
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