Solve for x by cross multiplying then isolating the variable:
cross multiply
15x=90 Isolate the variable
x=6
Solve for y by cross multiplying then isolating the variable:
cross multiply
9y=90 Isolate the variable
y=10
Answer:
84
Step-by-step explanation:
7*2*8
L*W*H
Let n represent the number.
-13×(n -60) = n +(-59)
-13n +780 = n -59
839 = 14n
839/14 = n = 59 13/14
The number is 59 13/14.
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Check
The difference between the number and 60 is
59 13/14 -60 = -1/14
-13 times that value is
-13*(-1/14) = 13/14
Compare that to the number plus -59
59 13/14 -59 = 13/14 . . . . . the same value, as required.
Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
We take the equation 4x+y=5 and subtract 4x from both sides to get
y = 5 - 4x
The answer to this question is <span>y=5−4x.</span>
