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IceJOKER [234]
3 years ago
5

Which two ratios form a proportion? A) 1 : 3 and 6 : 3 B) 1 : 3 and 3 : 6 C) 3 : 1 and 9 : 3 D) 3 : 1 and 3 : 9

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
8 0

Answer:

C is the answer

3 :1 and 9 :3

Step-by-step explanation:

a :b :: c:d = \frac{a}{b}  =  \frac{c}{d}

3 :1 and 9 :3

 = \frac{3}{1} and \frac{9}{3}

3:1 :: 9:3 = \frac{3}{1}  =  \frac{9}{3}

 

    3 =  3 so these two ratios are proportional

or another method is find the cross multiplication

\frac{3}{1} = \frac{9}{3}

i.e 3 × 3 = 9 × 1

  9 =9

so these two ratios are proportional

tamaranim1 [39]3 years ago
4 0

Answer:

c

Step-by-step explanation:

you have to set them up as a fraction and see if they are an equivalent fraction and if they are thats the proportion

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3 years ago
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How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

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Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

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We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

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