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IceJOKER [234]
3 years ago
5

Which two ratios form a proportion? A) 1 : 3 and 6 : 3 B) 1 : 3 and 3 : 6 C) 3 : 1 and 9 : 3 D) 3 : 1 and 3 : 9

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
8 0

Answer:

C is the answer

3 :1 and 9 :3

Step-by-step explanation:

a :b :: c:d = \frac{a}{b}  =  \frac{c}{d}

3 :1 and 9 :3

 = \frac{3}{1} and \frac{9}{3}

3:1 :: 9:3 = \frac{3}{1}  =  \frac{9}{3}

 

    3 =  3 so these two ratios are proportional

or another method is find the cross multiplication

\frac{3}{1} = \frac{9}{3}

i.e 3 × 3 = 9 × 1

  9 =9

so these two ratios are proportional

tamaranim1 [39]3 years ago
4 0

Answer:

c

Step-by-step explanation:

you have to set them up as a fraction and see if they are an equivalent fraction and if they are thats the proportion

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If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –
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Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is 5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5

<h3>To find the value of x :</h3>

First solving the given equation we have,

5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5

5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5

20\times (2)^{2-3x}=10\times (2)^{-2x}

20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}

20\times 4.(2)^{-3x}=10\times (2)^{-2x}

80(2)^{-3x}=10\times (2)^{-2x}

\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}

8(2)^{-3x}=(2)^{-2x}

\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}

(2)^{-3x}.(2)^{2x}=\frac{1}{2^3} ( by using the property \frac{1}{a^{-m}}=a^m )

2^{-3x+2x}=\frac{1}{2^3} ( by using the property a^m.a^n=a^{m+n} )

2^{-x}=\frac{1}{2^3}

\frac{1}{2^x}=\frac{1}{2^3} ( by using the property a^{-m}=\frac{1}{a^m} )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>
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Answer:

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7 0
3 years ago
X = 7 + 3y
pogonyaev
<h3>Given Equation:</h3>

x = 7 + 3y

or, x - 3y - 7 = 0 ........ (i)

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<h3>To Find:</h3>

The value of x and y.

<h3>Solution:</h3>

By dividing eq. ii by 2, we get

5/2x + 3y - 7 = 0 ........ (iii)

By adding eq. i and eq. iii, we get

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