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juin [17]
2 years ago
7

How many ions are in 0.5 moles of NaCl?

Chemistry
1 answer:
noname [10]2 years ago
4 0

Explanation:

Step 1: Write out the chemical formula of the compound.

Magnesium Chloride = MgCl^2

Step 2: Convert moles into number of compounds using Avogadro's number

0.5 moles MgCl^2 ⋅(6.022⋅10^23 - 1 mole MgCl^2)= 3.011⋅ 10^23

                               

Step 3: Determine how many Chloride ions there will be in 1 compound

There will be 2 Cl− ions in each compound (Cl^2 part)

Step 4: Multiply the number from Step 2 by the number in Step 3

3.011 ⋅ 10^23 ⋅ 2= 6.022 ⋅ 10^23

We do this because the ratio is 2 Cl− ions for every 1 compound.

In the case of finding how many ions in general (both sodium and chloride), we would multiply by 3 because there are 3 ions per 1 compound.

I hope this helped!

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A gas at 928 kpa, 129 C occupies a volume of 569 L. Calculate the volume at 319 kpa and<br> 32 C.
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Answer:

1255.4L

Explanation:

Given parameters:

P₁  = 928kpa

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The combined gas law application to this problem can help us solve it. It is mathematically expressed as;

           \frac{P_{1} V_{1} }{T_{1} }   = \frac{P_{2} V_{2} }{T_{2} }

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 take the units to the appropriate ones;

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P₂ = 319kpa in atm gives 3.15atm

P₁  = 928kpa gives 9.16atm

T₂  = 32°C gives 273 + 32  = 305K

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Input the values in the equation and solve for V₂;

        \frac{9.16  x 569}{402}   = \frac{3.15 x V_{2} }{305}

       V₂   = 1255.4L

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