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juin [17]
3 years ago
7

How many ions are in 0.5 moles of NaCl?

Chemistry
1 answer:
noname [10]3 years ago
4 0

Explanation:

Step 1: Write out the chemical formula of the compound.

Magnesium Chloride = MgCl^2

Step 2: Convert moles into number of compounds using Avogadro's number

0.5 moles MgCl^2 ⋅(6.022⋅10^23 - 1 mole MgCl^2)= 3.011⋅ 10^23

                               

Step 3: Determine how many Chloride ions there will be in 1 compound

There will be 2 Cl− ions in each compound (Cl^2 part)

Step 4: Multiply the number from Step 2 by the number in Step 3

3.011 ⋅ 10^23 ⋅ 2= 6.022 ⋅ 10^23

We do this because the ratio is 2 Cl− ions for every 1 compound.

In the case of finding how many ions in general (both sodium and chloride), we would multiply by 3 because there are 3 ions per 1 compound.

I hope this helped!

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Answer:

7.5 L of the 10% and 22.5 L of the 30% acid solution, she should mix.

Explanation:

Let the volume of 10% acid solution used to make the mixture = x L

So, the volume of 30% acid solution used to make the mixture = y L

Total volume of the mixture = <u>x + y = 30 L .................. (1) </u>

For 10% acid solution:

C₁ = 10% , V₁ = x L

For 30% acid solution :

C₂ = 30% , V₂ = y L

For the resultant solution of sulfuric acid:

C₃ = 25% , V₃ = 30 L

Using  

C₁V₁ + C₂V₂ = C₃V₃

10×x + 30×y = 25×30

So,  

<u>x + 3y = 75 .................. (2) </u>

Solving 1 and 2 we get,

<u>x = 7.5 L </u>

<u>y = 22.5 L</u>

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What equation represents the pressure of a gas under ideal conditions?
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P=nRTV
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How do you find the mass of an object?
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Write a definition for each word and use each word in a sentence.<br> crystallization and organic
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Look up the active ingredient in baking soda. Write a molecular and net ionic equation when that active ingredient is mixed with
Volgvan

Answer:

The active ingredients in baking soda (NaHCO3) are

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HCO3^-(aq) + CH3COOH(aq) → CH3COO^-(aq) + CO2(g) + H2O(l)

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