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juin [17]
2 years ago
7

How many ions are in 0.5 moles of NaCl?

Chemistry
1 answer:
noname [10]2 years ago
4 0

Explanation:

Step 1: Write out the chemical formula of the compound.

Magnesium Chloride = MgCl^2

Step 2: Convert moles into number of compounds using Avogadro's number

0.5 moles MgCl^2 ⋅(6.022⋅10^23 - 1 mole MgCl^2)= 3.011⋅ 10^23

                               

Step 3: Determine how many Chloride ions there will be in 1 compound

There will be 2 Cl− ions in each compound (Cl^2 part)

Step 4: Multiply the number from Step 2 by the number in Step 3

3.011 ⋅ 10^23 ⋅ 2= 6.022 ⋅ 10^23

We do this because the ratio is 2 Cl− ions for every 1 compound.

In the case of finding how many ions in general (both sodium and chloride), we would multiply by 3 because there are 3 ions per 1 compound.

I hope this helped!

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What is the pH of a 0.28 M solution of ascorbic acid
Nady [450]

Hey there!

Values Ka1 and Ka2 :

Ka1 => 8.0*10⁻⁵

Ka2 => 1.6*10⁻¹²

H2A + H2O -------> H3O⁺  + HA⁻

 Ka2 is very less so I am not considering that dissociation.

Now Ka = 8.0*10⁻⁵ = [H3O⁺] [HA⁻] / [H2A]

lets concentration of H3O⁺  = X then above equation will be

8.0*10−5 = [x] [x] / [0.28 -x

8.0*10−5 = x² /  [0.28 -x ]

x² + 8.0*10⁻⁵x  - 2.24 * 10⁻⁵

solve the quardratic equation

X =0.004693 M

pH = -log[H⁺]

pH = - log [ 0.004693 ]

pH = 2.3285

Hope that helps!

3 0
3 years ago
A bag of potato chips contains 585 mL of air at 20.0 C and a pressure of 765 mmHg. Assuming the bag does not break, what will be
Scorpion4ik [409]

Answer:

volume = 972.23ml

Explanation:

using general gas law

P1V1/T1 = P2V2/T2

765 x 585/293 = 443 x V2/282

1527.39 =443 x V2/282

1527.38 x 282 = 443 x V2

430695.78 = 443 x V2

V2 = 430695.68/443

V2 = 972.23mL

4 0
3 years ago
PLEASE HELP...with single replacement reaction w/ activity series
Blizzard [7]

Answer : The balanced chemical reaction will be:

AuI_4+2Br2\rightarrow AuBr_4+2I_2

Explanation :

Single replacement reaction : A chemical reaction in which the more reactive element replace the less reactive element.

It is represented as,

A+BC\rightarrow AC+B

In this reaction, A is more reactive element and B is less reactive element.

As per question, when gold (IV) iodide react with bromine to give gold (IV) bromide and iodine.

The balanced chemical reaction will be:

AuI_4+2Br2\rightarrow AuBr_4+2I_2

8 0
3 years ago
60 points please help me i will appreciate it!
VARVARA [1.3K]

Answer:

This is a pretty straightforward example of how an ideal gas law problem looks like.

Your strategy here will be to use the ideal gas law to find the pressure of the gas, but not before making sure that the units given to you match those used by the universal gas constant.

So, the ideal gas law equation looks like this

∣

∣

∣

∣

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a

a

P

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=

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R

T

a

a

∣

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−−−−−−−−−−−−−−−

Here you have

P

- the pressure of the gas

V

- the volume it occupies

n

- the number of moles of gas

R

- the universal gas constant, usually given as

0.0821

atm

⋅

L

mol

⋅

K

T

- the absolute temperature of the gas

Take a look at the units given to you for the volume and temperature of the gas and compare them with the ones used in the expression of

R

.

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Liters, L

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×

Notice that the temperature of the gas must be expressed in Kelvin in order to work, so make sure that you convert it before plugging it into the ideal gas law equation

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

T

[

K

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=

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+

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a

a

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−−−−−−−−−−−−−−−−−−−−−−−−

Rearrange the ideal gas law equation to solve for

P

P

V

=

n

R

T

⇒

P

=

n

R

T

V

Plug in your values to find

P

=

0.325

moles

⋅

0.0821

atm

⋅

L

mol

⋅

K

⋅

(

35

+

273.15

)

K

4.08

L

P

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

2.0 atm

a

a

∣

∣

−−−−−−−−−−−

The answer is rounded to two sig figs, the number of sig figs you have for the temperature of the gas.

6 0
2 years ago
Read 2 more answers
16. Magnesium has a density of 1.74g/cm3. A strip of magnesium metal measures 0.104m long and is 2.52mm wide. If the mass of the
KengaRu [80]

Answer:

228.1 m

Explanation:

Area of the magnesium strip = 0.104m  * 2.52 * 10^-3 = 2.62 * 10^-4 m^2

Density of Magnesium strip = 1.74g/cm3

Mass of magnesium strip = 0.104 g

But

density = mass/ area * thickness

density * area * thickness = mass

thickness  = mass/density * area

thickness  = 0.104 g/2.62 * 10^-4  * 1.74

thickness  = 0.104 g/ 4.56 * 10^-4

thickness  =  228.1 m

8 0
3 years ago
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