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3 years ago

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Write a balanced chemical equation based on the following description:

1 answer:

mina [271]3 years ago

8 0

Answer:

2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Explanation:

Let's consider the double displacement reaction in which aqueous silver nitrate reacts with aqueous nickel(II) chloride to produce solid silver chloride and aqueous nickel(II) nitrate.

AgNO₃(aq) + NiCl₂(aq) ⇒ AgCl(s) + Ni(NO₃)₂(aq)

We have 2 atoms of Cl on the left side, so we will add a stoichiometric coefficient 2 to AgCl.

AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Now, we have 2 atoms of Ag on the right side, so we will add a stoichiometric coefficient 2 to AgNO₃.

2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Now, the equation is balanced.

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1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?

Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

<u><em>We have the following data:</em></u>

Vo (initial volume) = 1.00 L

V (final volume) = 473 mL → 0.473 L

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)

P (final pressure) = ? (in atm)

<u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>

$P_0*V_0 = P*V$

$1*1 = P*0.473$

$1 = 0.473\:P$

$0.473\:P = 1$

$P = \dfrac{1}{0.473}$

$\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}$

<u><em>Answer: </em></u>

<u><em>The new pressure of the gas is 2.11 atm </em></u>

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$\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

3 0

3 years ago

The pOH of a solution is 6.0. Which statement is correct? Use p O H equals negative logarithm StartBracket upper O upper H super

castortr0y [4]

Answer:

The pH of the solution is 8.0.

Explanation:

taking the test rn

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3 years ago

Read 2 more answers

Explain how neutralization reactions are used in acid-base titrations.

nadya68 [22]

Acid-base tiltrations has DNA that can help in the process of neutralization. not so sure about it

8 0

3 years ago

A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235

trapecia [35]

Answer : The value of $\Delta E$ of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

$\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}$

Molar mass of helium = 4 g/mole

$\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole$

Now we have to calculate the heat.

Formula used :

$q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)$

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

$c_p$ = specific heat of helium = 20.8 J/mol.K

$T_1$ = initial temperature = 310.0 K

$T_2$ = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

$q=nc_p(T_2-T_1)$

$q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K$

$q=-19.5J$

Now we have top calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 1.21 L

$V_2$ = final volume = 0.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (0.99-1.21)L$

$w=0.22L.artm=0.22\times 101.3J=22.29J$

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the value of $\Delta E$ of the gas.

$\Delta E=q+w$

$\Delta E=(-19.5J)+22.29J$

$\Delta E=2.79J$

Therefore, the value of $\Delta E$ of the gas is 2.79 Joules.

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3 years ago

2. (1:25) How much does the moon pull on the Earth?

stepladder [879]

Answer:

a. more than the earth pull on the moon sorry if false

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