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aksik [14]
3 years ago
9

Write a balanced chemical equation based on the following description:

Chemistry
1 answer:
mina [271]3 years ago
8 0

Answer:

2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Explanation:

Let's consider the double displacement reaction in which aqueous silver nitrate reacts with aqueous nickel(II) chloride to produce solid silver chloride and aqueous nickel(II) nitrate.

AgNO₃(aq) + NiCl₂(aq) ⇒ AgCl(s) + Ni(NO₃)₂(aq)

We have 2 atoms of Cl on the left side, so we will add a stoichiometric coefficient 2 to AgCl.

AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Now, we have 2 atoms of Ag on the right side, so we will add a stoichiometric coefficient 2 to AgNO₃.

2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Now, the equation is balanced.

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Which equation agrees with the ideal gas law? mc005-1.jpg mc005-2.jpg mc005-3.jpg mc005-4.jpg
AlexFokin [52]
The ideal gas equation is pV = nRT


From that you can derive several equations, depending on which variables are fixed.


1) When n and T are fixed:

pV = nRT = constant


pV = constant => p1 V1 = p2 V2 => p1 / V2 = p2 / V1 ---> Boyle's Law


2) When n and V are constant:


p / T = nR/V = constant


p / T = constant => p1 / T1 = p2 / T2  ----> Gay - Lussac's Law


3) when n and p are constant


V / T = nR/p = constant   


V / T = constant => V1 / T1 = V2 / T2 ---> Charles' Law


4) When only n is constant


pV / T = nR = constant


pV / T = constant => p1 V1 / T1 = p2 V2 / T2 ----> Combined gas law.



There  you have the four equations that agree with the ideal gas law.  
7 0
3 years ago
Read 2 more answers
Which part of the mantle is still a solid but flows like a thick, heavy liquid?
marusya05 [52]

Hello!

Your answer is A, asthenosphere

<u>The asthenosphere is a part of the mantle</u>. It helps move the plates in the Earth.

It is <u>below the lithosphere,</u> between <u>80 and 200 km</u> below the surface.

Therfore, the asthenosphere is <u>the part of the mantle that is still a solid but flows like a thick, heavy liquid.</u>

<u />

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3 0
3 years ago
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klasskru [66]
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4 0
3 years ago
How many atoms of gold are in gold nugget with a mass of 4.25 g
Feliz [49]
Number of Atoms in Gold for given mass can be calculated using following formula,

              # of Moles  =  Number of Atoms / 6.022 × 10²³
Or,
             Number of Atoms  =  Moles × 6.022 × 10²³     ------- (1)    

Calculating Moles,
As,
                              Moles  =  Mass / M.mass
So,
                              Moles  =  4.25 g / 196.96 g/mol

                              Moles  =  0.0215

Putting value of mole in eq.1,

             Number of Atoms  =  0.0215 × 6.022 × 10²³

             Number of Atoms  =  1.299 × 10²²

Result:
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