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aksik [14]
3 years ago
9

Write a balanced chemical equation based on the following description:

Chemistry
1 answer:
mina [271]3 years ago
8 0

Answer:

2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Explanation:

Let's consider the double displacement reaction in which aqueous silver nitrate reacts with aqueous nickel(II) chloride to produce solid silver chloride and aqueous nickel(II) nitrate.

AgNO₃(aq) + NiCl₂(aq) ⇒ AgCl(s) + Ni(NO₃)₂(aq)

We have 2 atoms of Cl on the left side, so we will add a stoichiometric coefficient 2 to AgCl.

AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Now, we have 2 atoms of Ag on the right side, so we will add a stoichiometric coefficient 2 to AgNO₃.

2 AgNO₃(aq) + NiCl₂(aq) ⇒ 2 AgCl(s) + Ni(NO₃)₂(aq)

Now, the equation is balanced.

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Answer:

5.7

Explanation:

(C₂H₅)₃NHCl dissociates according to the following equation.

(C₂H₅)₃NHCl ⇒ (C₂H₅)₃NH⁺ + Cl⁻

The molar ratio of (C₂H₅)₃NHCl to (C₂H₅)₃NH⁺ is 1:1. Then, the concentration of (C₂H₅)₃NH⁺ is Ca = 0.166 M.

(C₂H₅)₃NH⁺ is the conjugate acid of (C₂H₅)₃N. Given the Kb of (C₂H₅)₃N, we can calculate Ka for (C₂H₅)₃NH⁺ using the following expression.

Ka × Kb = Kw

Ka = Kw / Kb

Ka = 1.0 × 10⁻¹⁴ / 5.2 × 10⁻⁴

Ka = 1.9 × 10⁻¹¹

(C₂H₅)₃NH⁺ dissociates according to the following equation.

(C₂H₅)₃NH⁺ ⇄ (C₂H₅)₃N + H⁺

We can calculate [H⁺] using the following expression.

[H⁺] = √(Ca × Ka) = √(0.166 × 1.9 × 10⁻¹¹) = 1.8 × 10⁻⁶

The pH is:

pH = -log [H⁺] = -log 1.8 × 10⁻⁶ = 5.7

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The solution would be like this for this specific problem:

 

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