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Burka [1]
3 years ago
9

What is the bond angle of a methane molecule that contains four hydrogen atoms bonded to one carbon atom?

Chemistry
2 answers:
IRINA_888 [86]3 years ago
6 0
Methane is a tetrahedral molecule where each C-H is kept as far away from the others as possible due to electron-electron repulsion, resulting in a bond angle of 109.5˚ (Technically 109˚ 28' but I would just use the decimal version if I were you).
Hope this helps!
Marta_Voda [28]3 years ago
5 0

Answer:

c

Explanation:on plato

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This is a straightforward dilution calculation that can be done using the equation

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where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

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Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

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