Answer:
2w + 2
Step-by-step explanation:
Width = w
Twice its width = 2*w =2w
2 inches more than twice its width = 2w + 2
Length = 2w + 2
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be

.
You're minimizing

subject to the constraint

. Note that

and

attain their extrema at the same values of

, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.
The Lagrangian is

Take your partial derivatives and set them equal to 0:

Adding the first three equations together yields

and plugging this into the first three equations, you find a critical point at

.
The squared distance is then

, which means the shortest distance must be

.
0.3 inches per hour, if I did the math correctly.
Hello!!
Well, the x-intercept is found when y = 0, so plug in y = 0:
-7x + 3(0) = 21
-7x = 21
x = -3
Therefore, the x-intercept of -7x + 3y = 21 is -3.
Hope this helps!! Let me know if you have ANY questions.
Solution:
1) Simplify \frac{1}{6}x to \frac{x}{6}
y=\frac{x}{6}-2
2) Add 2 to both sides
y+2=\frac{x}{6}
3) Multiply both sides by 6
(y+2)\times 6=x
4) Regroup terms
6(y+2)=x
5) Switch sides
x=6(y+2)
Done!