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3 years ago

The three shoppers spent 204$ in all . How much did each girl spend?

1 answer:

4 0

We would divide $204 by 3 to find out how much did each shopper spent. $204/3 is $68. So, each shopper spent $68. Hope this helped!

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HELP! LOTS OF POINTS

seropon [69]

Use the equation=
x^2+5^2=9^2
x^2+25=81
x^2+25-25=81-25
x^2=56
$\sqrt{x} = \sqrt{56}$
x=7.48331477355

5 0

2 years ago

Read 2 more answers

A carpenter bought 750 nails. Each nail has a mass of 5.2×10−3 kilogram. What is the total mass, in kilograms, of the nails the

lawyer [7]

The total mass, in kilograms, of the nails the carpenter bought is 3.9 kilogram

<h3>Solution:</h3>

Given that carpenter bought 750 nails

Each nail has a mass of $5.2 \times 10^{-3}$ kilogram

To find: total mass, in kilograms of the nails bought

The total mass of the nails bought can be found out by multiplying number of nails bought by mass of each nail

Number of nails bought = 750

Mass of each nail = $5.2 \times 10^{-3}$ kilogram

total mass of the nails bought = number of nails bought x mass of each nail

$\text {total mass of the nails bought }=750 \times 5.2 \times 10^{-3}$

$\text {total mass of the nails bought }=3900 \times 10^{-3}=\frac{3900}{1000}=3.9$

Thus the total mass of nails bought is 3.9 kilogram

4 0

2 years ago

Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon

Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

Step-by-step explanation

taking into account the truth table for the conditional connective:

p | q | p→q

T | T | T

T | F | F

F | T | T

F | F | T

(a) and (b) can be seen from truth tables:

for (a) p∧q:

p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q

T | T | F | F | T | T

T | F | T | T | F | F

F | T | F | T | F | F

F | F | T | T | F | F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

p | q | ¬p | ¬p→q | p∨q

T | T | F | T | T

T | F | F | T | T

F | T | T | T | T

F | F | T | F | F

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0

2 years ago

X^2=4x-15 solve with Quadratic formula

bulgar [2K]

Answer:

$x=2+i\sqrt{11}$

$x=2-i\sqrt{11}$

Step-by-step explanation:

we have

$x^{2} =4x-15$ -------> $x^{2}-4x+15=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-4x+15=0$

$a=1\\b=-4\\c=15$

substitute in the formula

$x=\frac{-(-4)(+/-)\sqrt{-4^{2}-4(1)(15)}} {2(1)}$

$x=\frac{4(+/-)\sqrt{16-60}} {2}$

Remember that

$i=\sqrt{-1}$

$x=\frac{4(+/-)\sqrt{-44}} {2}$

$x=\frac{4(+/-)2i\sqrt{11}} {2}$

$x=\frac{4(+)2i\sqrt{11}}{2}=2+i\sqrt{11}$

$x=\frac{4(-)2i\sqrt{11}}{2}=2-i\sqrt{11}$

7 0

2 years ago

The angle of elevation to the top of a 30 story skyscraper is measured to be 3 degrees from a point on the ground 2,000 feet fro

Leto [7]

You have an angle of elevation of 3 degrees and you're 2000 ft from base of 30 story building.
Draw a picture of this. Then tan(3) = ht of bldg/2000 
I get a height of 104.82 ft rounded to 2 dp. 

5. Ok. use the Pythagorean Theorem here to find the hypotenuse of the right triangle 
hypt = sqrt(50^2 + 9^2) 
Now sine of the angle of elevation is 50/hypt. = 0.984 or 0.98 to 2 dp.

4 0

2 years ago