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3 years ago

Help please.

Mathematics

1 answer:

lubasha [3.4K]3 years ago

7 0

Answer:

C. -x^5 + 7x⁴ + 8x² - 9x - 5

Step-by-step explanation:

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the area of a pentagon increased by 27 is the same as four times the difference of area and 15. what is the area of the pentagon

AfilCa [17]

This can be written as:
a+27=4(15-a)
now to work it out
a+27=4(15-a)
a+27=60-4a
4a+27=60
4a=33
a=8.25

<span>hope this helps :)</span>

6 0

3 years ago

I need help with this. its dividing polynomials

Alex Ar [27]

Answer:

I don't know how to solve it

6 0

3 years ago

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in a rectangular triangle ABC A=90° AB=4 and AC=3. Find the BC hypotenuse using pythagorean theorem.

Alex Ar [27]

Answer:

BC=5

Step-by-step explanation:

BC^2= AB^2 + AC^2

x^2= 4^2 + 3^2

x^2= 16 +9

x^2= 25

${ \sqrt{25} }$

x= 5

5 0

3 years ago

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Find all values of a such that (a-3)/sqrta=-sqrta

Mariana [72]

Answer:

From the Pythagorean theorem...

[ distance between (a, 7) and (2, 1) ]2 = [a - 2]2 + [7 - 1]2

And they tell us that the distance equals 3√5 , so

[ 3√5 ]2 = [a - 2]2 + [7 - 1]2

45 = [a - 2]2 + 36

9 = [a - 2]2

±√9 = a - 2

± 3 = a - 2

± 3 + 2 = a

a = 3 + 2 = 5 or a = -3 + 2 = -1

and

5 + -1 = 4

Step-by-step explanation:

hope dis helps

3 0

3 years ago

Consider the polynomials p(x) = 3x + 27x^2 and q(x)= 2 . Find the x -coordinate(s) of the point(s) of intersection of these two

Tom [10]

Answer:

The x -coordinate(s) of the point(s) of intersection of these two polynomials are $x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333$

The sum of these x -coordinates is $\frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}$

Step-by-step explanation:

The intersections of the two polynomials, p(x) and q(x), are the roots of the equation p(x) = q(x).

Thus, $3x + 27x^2=2$ and we solve for x

$3x+27x^2-2=2-2\\27x^2+3x-2=0\\\left(27x^2-6x\right)+\left(9x-2\right)\\3x\left(9x-2\right)+\left(9x-2\right)\\\left(9x-2\right)\left(3x+1\right)=0$

Using Zero Factor Theorem: = 0 if and only if = 0 or = 0

$9x-2=0\\9x=2\\x=\frac{2}{9}$

$3x+1=0\\3x=-1\\x=-\frac{1}{3}$

The solutions are:

$x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333$

The sum of these x -coordinates is

$\frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}$

We can check our work with the graph of the two polynomials.

4 0

4 years ago