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Paul [167]
2 years ago
9

Molly is studying two number pattems. Patter A starts at 0 and has the rule "add 3." Pattern B starts at 0 and has the rule "add

6." What is the relationship betwee
corresponding terms in the two patterns?
The terms in Pattem A are 3 times the corresponding terms in Pattem B.
The terms in Pattem A are 2 times the corresponding terms in Pattern B.
The terms in Pattem A are
1
the corresponding terms in Pattem B.
2.
The terms in Pattem A are
1
the corresponding terms in Pattem B

Mathematics
1 answer:
Gnesinka [82]2 years ago
4 0

Answer: See explanation..

Step-by-step explanation: Click here for your answer brainly.com/question/27458283

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Agata [3.3K]
THE ANSWER IS
<span>d.(2,3)</span>
8 0
3 years ago
Find the distance between (5, 9) &amp; (-7, -7). Round to the nearest tenth.
coldgirl [10]
Distance equals end minus start

(-7,-7)-(5,9)=
(-7-5,-7-9)=(-12,-16)

(-12,-16) gives us the distance point coordinates. Now to find the magnitude we can take sqrt((-12)^2+(-16)^2)=20

So the distance between the two points is 20

I hope this helps
8 0
2 years ago
Find the polynomial of minimum degree, with real coefficients, zeros at
drek231 [11]

Answer:

\huge\boxed{p(x)=4x^3-20x^2+4x+300}

Step-by-step explanation:

\text{If}\ x=4\pm3i\ \text{and}\ x=-3\ \text{are the zeros of a polynomial, then it has  a form:}\\\\p(x)=\bigg(x-(4-3i)\bigg)\bigg(x-(4+3i)\bigg)\bigg(x-(-3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x-4+3i)(x-4-3i)(x+3)\bigg(r(x)\bigg)\\\\p(x)=\underbrace{\bigg((x-4)+3i\bigg)\bigg((x-4)-3i\bigg)}_{\text{use}\ (a+b)(a-b)=a^2-b^2}(x+3)\bigg(r(x)\bigg)\\\\p(x)=\bigg((x-4)^2-(3i)^2\bigg)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2

p(x)=(x^2-2(x)(4)+4^2-3^2i^2)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ i^2=-1\\\\p(x)=(x^2-8x+16-9(-1))(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+16+9)(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+25)(x+3)\bigg(r(x)\bigg)\qquad\text{use FOIL}:\ (a+b)(c+d)=ac+ad+bc+bd\\\\p(x)=\bigg((x^2)(x)+(x^2)(3)+(-8x)(x)+(-8x)(3)+(25)(x)+(25)(3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x^3+3x^2-8x^2-24x+25x+75)\bigg(r(x)\bigg)\qquad\text{combine like terms}\\\\p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)

\text{The y-intercept is at 300}.\\\\\text{For}\ w(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+...+a_1x+a_0\\\\\text{y-intercept is}\ a_0\\\\\text{Therefore for}\ p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)\\\\\text{y-intercet is}\ 75\bigg(r(x)\bigg)\\\\75\bigg(r(x)\bigg)=300\qquad\text{divide both sides by 75}\\\\r(x)=4\\\\\text{Finally:}\\\\p(x)=(x^3-5x^2+x+75)(4)\qquad\text{use the distributive property}\\\\p(x)=(x^3)(4)+(-5x^2)(4)+(x)(4)+(75)(4)\\\\p(x)=4x^3-20x^2+4x+300

7 0
3 years ago
A repair person charges $25 per hour plus and initial service charge of $30.
Norma-Jean [14]

Answer:

The repair person did 5 hours of work.

Step-by-step explanation:

155 = 25x + 30

125 = 25x

5 = x

6 0
3 years ago
Read 2 more answers
What is the value of x? Round to the nearest tenth.
kotykmax [81]

Answer:

27.5

Step-by-step explanation:

first you find what 30x30 is as A squared plus B squared is equal to C squared. your A is 12 and your C is 30.

so!

30x30 is 900

12x12 is 144

subtract 144 from 900 and you get 756. once you find the square root you get 27.49. then round up to 27.5

5 0
3 years ago
Read 2 more answers
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