(x² - 1)^-2/3
∛(x² - 1)-²
∛(1/(x² - 1)(x² - 1))
∛(1/(x^4 - x² - x² + 1))
∛(1/(x^4 - 2x² + 1))
1/x^4/3 - 1.25992105x^2/3 + 1
Hello :
the circumference of a circle is P : P = <span>2π×r r : ridus
</span> P = 2π×r = π× L because : 2r = L
you can find the diameter L : L = P/π
Answer:
4=0
Step-by-step explanation:
Simplifying
(-9p + 7) + -1(-9p + 3) = 0
Reorder the terms:
(7 + -9p) + -1(-9p + 3) = 0
Remove parenthesis around (7 + -9p)
7 + -9p + -1(-9p + 3) = 0
Reorder the terms:
7 + -9p + -1(3 + -9p) = 0
7 + -9p + (3 * -1 + -9p * -1) = 0
7 + -9p + (-3 + 9p) = 0
Reorder the terms:
7 + -3 + -9p + 9p = 0
Combine like terms: 7 + -3 = 4
4 + -9p + 9p = 0
Combine like terms: -9p + 9p = 0
4 + 0 = 0
4 = 0
Solving
4 = 0
Answer:
∠STP = 90°
Step-by-step explanation:
The diagonals of a square are perpendicular bisectors of each other, hence
∠STP = 90°
