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Nonamiya [84]
3 years ago
9

Write the equation of a line that would be parallel to the line given. 2 10) y=-2/3x+10

Mathematics
1 answer:
Tema [17]3 years ago
6 0

Answer:

y= -2/3x+11

Step-by-step explanation

you just have to change the number without an x

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2 divided by 1/3 in simpleast form
leva [86]

Answer:

6

Step-by-step explanation:

When dividing by a fraction flip it over and multiply

2 / (1/3) = 2 * 3/1

2 / (1/3) = 6/1

2 / (1/3) = 6

8 0
3 years ago
What percent of 208 is 197.6
ikadub [295]
Your percent is going to be <span>-203.008</span>
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Minutes played points scored
stepan [7]
I think it's A. Sorry if I get it wrong.
7 0
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A cubical tank of edge 12 cm is half filled with water. The water is poured into an empty rectangular tank measuring 10 cm by 8
qaws [65]

Answer:

3040000mm³

Step-by-step explanation:

Volume of a cube = a³ ; a = size of edge

Volume of cubical tank = 12³ = 12 * 12 * 12 = 1728 cm³

Half filled cube = 1728 / 2 = 864 cm³

Volume is f rectangular tank :

V = length * width * height

V = 10 * 8 * 7 = 560 cm³

Volume of water left in cubical tank :

(864 - 560) = 304cm³

1cm³ = 1000mm³

304cm³ = 304 * 1000 = 3040000mm³

3 0
3 years ago
A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The
Vladimir [108]

Using the Sine rule,

\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

A^0+P^0+B^0=180^0\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}

Using the side rule to find the length of wire BP,

\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0
1 year ago
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