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notsponge [240]
2 years ago
5

Randy is starting a beehive so that he can have fresh

Mathematics
1 answer:
klemol [59]2 years ago
8 0

Answer:

1,280

Step-by-step explanation:

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Find the value of n<br> (2n + 4)º
MatroZZZ [7]

Answer:

I don't recognize this problem, please make sure the input is complete.

Step-by-step explanation:

it that the full problem?

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3 years ago
PLEASE HELP ME!!! <br> Solve in substitution form step by step please
romanna [79]

Answer:

3. (3,-4)

Step-by-step explanation:

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2 years ago
Yo I need this as soon as possible
joja [24]

Answer:

Step-by-step explanation:

So, if we know that 25 is the area of the square, that means that each side is 5.  That also means the diameter of the circle is 5, so the radius is 2.5.  Now, we can input the radius into the circumference formula for a circle, which is 2πradius.  So, 2π2.5 which equals 5π, or about 15.71

3 0
3 years ago
A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the
hoa [83]

Answer:

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone ≈ 12.57 m²

Step-by-step explanation:

The given parameters are;

The height of the cone = 5 m

The base radius of the cone  = 2 m

The angle which the A\hat OC = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone

The angle between [CF]  and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°  

∴ The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

8 0
3 years ago
Tres amigos: Andrés, Braulio y Ciro, juegan 3 apuestas
skelet666 [1.2K]

Answer:

La persona que ganó más dinero fue Braulio por S/.16

Step-by-step explanation:

Deje que la cantidad inicial sea Andrés X, Braulio Y y Ciro Z

Luego, dado que cada uno pierde una apuesta en el orden presentado, tenemos;

Después de la primera apuesta, tenemos;

Andrés X-Y-Z, Braulio (Y + Y), Ciro (Z + Z)

En la segunda apuesta, tenemos;

2 (X-Y-Z), 2Y - (X-Y-Z) - 2Z, 2Z + 2Z

2 (X-Y-Z), 3Y - X -Z, 4Z

En el tercero

4 (X-Y-Z), 6Y - 2X - 2Z, 4Z-2 (X-Y-Z) - (3Y - X -Z)

4 (X-Y-Z), 6Y - 2X - 2Z, 7Z - X - Y

4 (X-Y-Z) = 0.48 .............................. (1)

6Y - 2X - 2Z = 0.56 ...................... (2)

7Z - X - Y = 0.28 ............................ (3)

Multiplicamos las ecuaciones (2) por 2 y restamos la ecuación (1), tenemos;

12Y - 4X - 4Z - 4X + 4Y + 4Z = 0.56 * 2 - 0.48 = 0.64

16Y - 8X = 0.64 ...................... (4)

Multiplicamos las ecuaciones (2) por 7/2 y sumamos a la ecuación (3), tenemos;

21Y - 7X - 7Z + 7Z - X - Y = 7/2 * 0.56 + 0.28

20Y - 8X = 2.24 ...................... (5)

Restando la ecuación (4) de la ecuación (5) tenemos;

20Y - 8X - 16Y - 8X = 2.24 - 0.64 =

4Y = 1.6

Y = 1.6 / 4 = 0.4

De la ecuación (5), tenemos;

20Y - 8X = 20 * 0.4 - 8X = 2.24

8X = 8 - 2.24 = 5.76

X = 5,76 / 8 = 0,72

De la ecuación (3), tenemos;

7Z - X - Y = 7Z - 0.72 - 0.4 = 0.28

7Z = 1.4

Z = 1.4 / 7 = 0.2

Por lo tanto tienen inicialmente

X₁ = 0.72

Y₁ = 0.4

Z₁ = 0.2

Después de jugar tienen;

X₂ = 0.48

Y₂ = 0.56

Z₂ = 0.28

Los cambios son

Andrés 0.48 - 0.72 = -0.24

Braulio; 0.56 - 0.4 = 0.16

Ciro 0.28 - 0.2 = 0.08

La persona que ganó más dinero fue Braulio por S/.16

7 0
3 years ago
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