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zzz [600]
2 years ago
12

3 If f(x) = x2 and g(x) = x + 6, find g(f(0)). A. -6 B. 6 C. 12 D. 36

Mathematics
1 answer:
harkovskaia [24]2 years ago
4 0

Answer:

6

Step-by-step explanation:

g(f(0)) means that the input of f(x) is 0 and this value of f(x) found is the input of g(x). This is known as composite functions.

Let's find the value of f(0).

f(x)= x²

f(0)= 0²

f(0)= 0

Now, we can find the value of g(f(0)).

g(x)= x +6

g(f(0))

= g(0)

= 0 +6

= 6

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Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

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Step-by-step explanation:

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