The correct sequence of events in protein synthesis is transcription, then translation.
6:$9
Multiply both by 2 (because 12/6=2)
And get 12:$18
3:7
Multiply both by 2 (because 14/7=2)
And get 6:14
6:3
Multiply both by 8 (48/6=8)
And get 48:24
Always label your units. Sorry I’m lazy
Answer:
the answer is 500. hope this helps give me brainlest please.
Answer:13.8
Step-by-step explanation:
Just add 6.3 4 and 3.5
I'll assume the ODE is actually

Look for a series solution centered at
, with



with
and
.
Substituting the series into the ODE gives





- If
for integers
, then




and so on, with

- If
, we have
for all
because
causes every odd-indexed coefficient to vanish.
So we have

Recall that

The solution we found can then be written as

