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Diano4ka-milaya [45]
3 years ago
5

add the term that makes the given expression into a perfect square write the result as the square of a bracketed expression a sq

uare + 8a​
Mathematics
1 answer:
Jet001 [13]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

a² + 8a

using the method of completing the square

add ( half the coefficient of the a- term)²

a² + 2(4)a + 16

= (a + 4)²

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17/12

Step-by-step explanation:

hope this helped your welcome

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Geometry Helps please<br> (Only correct Answers only please) Thanks!
nlexa [21]

Answer:

301.44 cubic units

Step-by-step explanation:

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7 0
3 years ago
F(x)=x2 what is g(x)?
Oksi-84 [34.3K]

g(x) = (1/4)x^2 . correct option C) .

<u>Step-by-step explanation:</u>

Here we have , f(x)=x^2  and we need to find g(x) from the graph . Let's find out:

We have ,  f(x)=x^2   . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !

A . g(x) = (1/4x)^2

Putting (2,1) in equation g(x) = (x/4)^2 , we get :

⇒ g(2)= (\frac{2}{4} )^2

⇒ 1\neq \frac{1}{4}

Hence , wrong equation !

B . g(x) = 4x^2

Putting (2,1) in equation g(x) = 4x^2 , we get :

⇒ g(2)=4(2)^2

⇒ 1\neq 64

Hence , wrong equation !

C . g(x) = (1/4)x^2

Putting (2,1) in equation g(x) = (1/4)x^2 , we get :

⇒ g(2)= (\frac{1}{4} )2^2

⇒ 1= 1

Hence , right equation !

D . g(x) = (1/2)x^2

Putting (2,1) in equation g(x) = (1/2)x^2 , we get :

⇒ g(2)= (\frac{1}{2} )2^2

⇒ 1\neq 2

Hence , wrong equation !

Therefore , g(x) = (1/4)x^2 . correct option C) .

8 0
4 years ago
I need help with this question :/
Setler79 [48]

Answer:

see explanation

Step-by-step explanation:

Note there is a common ratio between consecutive terms of the sequence, that is

- 450 ÷ 15 = 13500 ÷ - 450 = - 405000 ÷ 13500 = - 30

Thus to obtain the next term in the sequence multiply the previous term by - 30

start with 15 and multiply by - 30

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4 years ago
The perimeter of a rectangle is 68m and its lenght is 24m. find its breadth,area, and diagonal​
seropon [69]

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