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jarptica [38.1K]
1 year ago
15

Determine the sine, cosine, and tangent to the angle A sun 0=12/15

Mathematics
1 answer:
DENIUS [597]1 year ago
5 0

Answer:

Cos θ = 13/15

Tan θ= 12/13

Step-by-step explanation:

We are given;

Sin θ = 12/15

From trigonometric ratios, we know that;

Sin θ = opp/hyp

Cos θ = adj/hyp

Tan θ = opp/adj

Thus, since Sin θ = 12/15, then;

Adjacent side = √(15²- 12²)

Adhacent side = √169

Afjacent side =13

Thus;

Cos θ = 13/15

Tan θ= 12/13

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Check all of the steps that would be used to solve this equation: 2(x-5)=24
aliya0001 [1]
X=17

Distribute 2(x-5)
You are left with 2x-10=24
You then want to get 2x by itself so add 10 on both sides so that you get 2x=34
Isolate x completely by dividing by 2 on both sides which then leaves you with x=17
8 0
3 years ago
Meteorologists in Texas want to increase the amount of rain delivered by thunderheads by seeding the clouds. Without seeding, th
Dafna11 [192]

Answer:

<em>There is no significant difference in the amount of rain produced when seeding the clouds.</em>

Step-by-step explanation:

Assuming that the amount of rain delivered by thunderheads follows a distribution close to a normal one, we can formulate a hypothesis z-test:

<u>Null Hypothesis </u>

\bf H_0: Average of the amount of rain delivered by thunderheads without seeding the clouds = 300 acrefeet.

<u>Alternative Hypothesis </u>

\bf H_a: Average of the amount of rain delivered by thunderheads by seeding the clouds > 300 acrefeet.

This is a right-tailed test.

Our z-statistic is  

\bf z=\frac{370.4-300}{300.1/\sqrt{30}}=1.2845

We now compare this value with the z-critical for a 0.05 significance level. This is a value \bf z^* such that the area under the Normal curve to the left of \bf z^* is less than or equal to 0.05

We can find this value with tables, calculators or spreadsheets.

<em>In Excel or OpenOffice Calc use the function </em>

<em>NORMSINV(0.95) </em>

an we obtain a value of  

\bf z^* = 1.645

Since 1.2845 is not greater than 1.645 we cannot reject the null, so the conclusion that can be drawn when the significance level is 0.05 is that there is no significant difference in the amount of rain produced when seeding the clouds.

8 0
3 years ago
Find the functional values g (-3), g (0), and g (5) for the compound function.
Zinaida [17]

Answer:

g(-3)=7

g(0)=7

g(5)=\dfrac15

Step-by-step explanation:

g(x) =\begin{cases}7 & \text{if } x \leq 0 \\ \\\dfrac{1}{x} & \text{if } x > 0\end{cases}

This means:

  • when x is equal to zero or less than zero, g(x) will always be 7.
  • when x is more than zero, g(x) is \frac{1}{x}

\implies g(-3)=7

\implies g(0)=7

\implies g(5)=\dfrac15

5 0
1 year ago
Read 2 more answers
Basher collected 4 1/3 basket of peaches and Orchard if each basket holds 21
miv72 [106K]
To do this you times 3 by 4 and add it on to the numerator of the fraction, to turn it into a top heavy fraction:
3*4 = 12
1+12/3 = 13/3

Then you multiply the numerator by 21 to work out what 21 times the fraction is:
13*21/3 = 273/3

Then you can divide 273 by 3 to get the final answer:
273/3 = 91

He will have 91 peaches overall.
Hope this helps! :)
6 0
3 years ago
Solve -1/2w-3/5=1/5w
elena55 [62]
Very easy:

Common denominator:
-5/10w - 3/5 = 2/10w

- 3/5 = 7/10w

-30 = 35w

-30/35 = w

-6/7 = w


That's how you do it mate ;)
8 0
2 years ago
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