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jarptica [38.1K]
2 years ago
15

Determine the sine, cosine, and tangent to the angle A sun 0=12/15

Mathematics
1 answer:
DENIUS [597]2 years ago
5 0

Answer:

Cos θ = 13/15

Tan θ= 12/13

Step-by-step explanation:

We are given;

Sin θ = 12/15

From trigonometric ratios, we know that;

Sin θ = opp/hyp

Cos θ = adj/hyp

Tan θ = opp/adj

Thus, since Sin θ = 12/15, then;

Adjacent side = √(15²- 12²)

Adhacent side = √169

Afjacent side =13

Thus;

Cos θ = 13/15

Tan θ= 12/13

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Your answer is <em>3/7</em>
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If fx()=8-10x and g(x)=5x+4, what is the value of (fg)(-2)
lyudmila [28]

So, we are looking for F of G of 2. So, we need to work backwards and find G(x) first.


g(-2)=5(-2)+4\\g(-2)=-6

So we know that g(-2) = -6, now we take thatt -6 and plug in into f(x)

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7 0
3 years ago
Please help me with this!!
Naddik [55]

Step-by-step explanation:

To find the y-coordinate points we need to evaluate the function for all the x values in the table. In other words, we need to replace x with each value in our given function and simplify.

- For x = 0

f(x)=(x-2)^2-5

f(0)=(0-2)^2-5

f(0)=(-2)^2-5

f(0)=4-5

f(x)=-1

Since x=0 and y=-1, our first point is (0, -1)

- For x = 1

f(x)=(x-2)^2-5

f(1)=(1-2)^2-5

f(1)=(-1)^2-5

f(1)=1-5

f(x)=-4

Our second point is (1, -4)

- For x = 2

f(x)=(x-2)^2-5

f(2)=(2-2)^2-5

f(2)=(0)^2-5

f(x)=-5

Our third point is (2, -5)

- For x = 3

f(x)=(x-2)^2-5

f(3)=(3-2)^2-5

f(3)=(1)^2-5

f(3)=1-5

f(x)=-4

Our fourth point is (3, -4)

- For x = 4

f(x)=(x-2)^2-5

f(4)=(4-2)^2-5

f(4)=(2)^2-5

f(4)=4-5

f(x)=-1

Our fifth point is (4, -1)

Now we just need to plot each point in our coordinate plane and join them with the parabola as you can see in the attached picture.

3 0
3 years ago
How many odd numbers are there between twenty and forty?
inna [77]

Answer:

Total 10

Step-by-step explanation:

21. 23, 25, 27, 29, 31 , 33, 35, 37, 39.

hope this helps you

5 0
2 years ago
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