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kkurt [141]
2 years ago
5

Sam made $80,000 as a financial analyst her first year out of college. She calculated her above-the-line deductions to be $5,500

, her itemized deductions to be $7,000, and the standard deduction is $12,550. What deductions is Sam allowed to take that will minimize her taxes owed?
*
She can take the $5,500 and the $12,550 for $18,050 in deductions
She can take the $7,000 and the $12,550 for $19,550 in deductions
She can take the $5,500 and the $7,000 for $12,500 in deductions
She can take all three for $25,050 in deductions
Mathematics
1 answer:
andrezito [222]2 years ago
6 0

Answer:

brainly banned me :( (prob going to do it again LOL)

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Atherine has $54. She plans to spend more than $20 of the money for a painting canvas. The rest will go toward paints. Each tube
horsena [70]

I think that she could buy 3 tubes of paint because that's $25.50 and that gives you 28.50 for the canvas.

4 0
3 years ago
Ed's new car has a value of $23,500, but it is expected to depreciate at a rate of 7.5% per year. If you were to write an expone
Delicious77 [7]

Answer:

0.925 or 92.5%

Step-by-step explanation:

y=a(1-b)^x

decay factor is 1-b <- and the part we care about

b is 7.5%=0.075

1-0.075

=0.925

I'm a little rusty on exponential rates, but I hope this helps!

3 0
3 years ago
What is 9/11 +2/3 and show the work
erica [24]

Answer:

9/11 = 27/33

2/3 = 22/33

27/33 + 22/33 = 49/33

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
A part of Jennifer’s work is to solve the equation 2(6x^2-3)=11x^2-x is shown below
kotykmax [81]

Answer:

Step-by-step explanation:

2(6x² - 3) = 11x² - x

2*6x² - 2*3 = 11x² - x

12x² - 6 = 11x² -x

Subtract 11x² from both sides

12x² - 11x² - 6 = -x

x² - 6 = -x

x² + x - 6= 0

Sum =1

Product = -6

Factors =  3 , (-2)              { 3*(-2)  = -6   & 3 +(-2) = 1}

x² + 3x - 2x - 6 = 0

x(x + 3) - 2(x + 3)= 0

(x +3)(x - 2) = 0

7 0
3 years ago
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