The correct answer is C A single-celled protist divides into two cells, and each one becomes another protist.
Answer:
See
Explanation:
Given:
Brown allele (B) is dominant over the white allele (b).
It will be assumed that the alleles are not related to the X and Y chromosomes.
See attached diagram for details of the general case (for both homo-zygous and hetero-zygous parents)
For both parents hetero-zygous,
P1:
Genotype: Bb (100%)
Phenotype: brown (100%)
F1:
Genotypes : BB, Bb, bB and bb in equal proportions, i.e.
BB (25%), Bb (50%), bb (25%)
Phenotypes: 75% brown (from BB and Bb), 25% white (from bb)
Answer:
C) 50%
Explanation:
If wavy hair is heterozygous then wavy is dominent and curly is recessive. So the alles for wavy would be Ww and for curly it would be ww. Put that on a punnet square and it is 50-50
Ans.
Sex-linked genes are those genes that found on sex-chromosomes (X and Y chromosomes) and their phenotypic expression for a trait depends on the gender of the offspring.
Most of the sex-linked genes are present on X chromosomes as X chromosomes have more number of genes as they are made up of more DNA as compared to Y chromosome.
However, male individuals are more likely to exhibit the sex-linked traits. It is because most of the sex-linked traits are recessive and males have only one copy of X chromosome, while females have two copies of X chromosome. One mutated copy in male can exhibit the trait, while in females, both of the mutated copies are required to exhibit that trait.
