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Anna007 [38]
2 years ago
6

How much should you put in an investment paying a simple interest rate of​ 5% if you needed​ $4000 in eighteen​ mont

Mathematics
1 answer:
Eddi Din [679]2 years ago
6 0

now, there are 12 months in a year, so 18 months is really 18/12 of a year, thus

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$4000\\ P=\textit{original amount deposited}\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\to \frac{18}{12}\dotfill &\frac{3}{2} \end{cases} \\\\\\ 4000=P[1+(0.05)(\frac{3}{2})]\implies 4000=P(1.075) \\\\\\ \cfrac{4000}{1.075}=P\implies 3720.93\approx P

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Answer:

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To solve this, first we'll find the area of the rectangle A,

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now we'll find the width of rectangle B,
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finally we'll find the length of rectangle B,
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