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ale4655 [162]
3 years ago
10

It math bad at it please help:);-)

Mathematics
1 answer:
abruzzese [7]3 years ago
6 0

Answer:

It is -1/7 x (6p-1)

Step-by-step explanation:

Btw download photomath on your phone it helps alot

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What value is equivalent to 3 x 12 / (4 + 2) ? Answer to work the problem is 6. Is that the value? I’m reading the expression as
IceJOKER [234]

Answer:

6

Step-by-step explanation:

<u>3x12</u> = <u>36</u>

(4+2)    6

simplify

36/6=6

The value is indeed 6 and there shouldn't be a variable because if there is, then there should be a variable in the question.

3 0
3 years ago
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Can someone help me algebra 1
ANEK [815]
Yes I can but what’s the question???
7 0
3 years ago
Find the area of the circle. Round your answer to the nearest hundredth with 3in i really need help
REY [17]

Answer:

The area of the circle with a 3-inch diameter is 7.07 square inches.

Step-by-step explanation:

The formula for the area of a circle is

A = πr²

If you are given diameter, take half of that to get the radius:  3 ÷ 2 = 1.5

Then take the radius, 1.5 and square it  (multiply by itself)  1.5 × 1.5 = 2.25

Then multiply r² times pi. You can use 3.14. (sometimes you will need 3.14159)

2.25 × 3.14 = 7.065

Your instructions are to "round to the nearest hundredth" so you look to the thousandth place and see a 5. Rules fro rounding: "If the number is 5 or higher, add 1 to the place you are rounding to. If 4 or less, leave the place as it is."

You see a 6 in the hundredths place. Add 1. so the rounded answer is 7.07.

Then you put in the units measure. Inches are given, so the Area will be square inches

7.07 in²

3 0
3 years ago
4+ 10(5-3) + 4 +62 is what <br> 18<br> 42<br> 21<br> 45
LenaWriter [7]

Answer:

18

Step-by-step explanation:

i k

Just todo the test so its tje ansiedad

4 0
2 years ago
True or False? Each point on the perpendicular bisector of a segment is equidistant from the endpoints of the segment.
Bogdan [553]
True

The Perpendicular Bisector Theorem states, If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment
3 0
3 years ago
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