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Bezzdna [24]
2 years ago
6

Find the volume of the compound shape.​

Mathematics
2 answers:
SpyIntel [72]2 years ago
7 0

half of a sphere:

=56.55 cm^3

cone:

=94.25 cm^3

all together:

150.80 cm^3

arsen [322]2 years ago
4 0
<h3>Volume of the hemisphere:</h3>

v =  \frac{2}{3} \pi {r}^{3}

v =  \frac{2}{3}  \times \pi \times  {3}^{3}

v = 56.55 \:  {cm}^{3}

<h3>Volume of the cone:</h3>

v =  \frac{1}{3} \pi {r}^{2} h

v =  \frac{1}{3}  \times \pi \times  {3}^{2}  \times 10

v = 94.25 \:  {cm}^{3}

<h3>Total volume:</h3>

v = 56.55 + 94.25

v = 150.80 \:  {cm}^{3}

<u>Therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>compound</u><u> </u><u>shape</u><u> </u><u>is</u><u> </u><u>150.80</u><u> </u><u>cubic</u><u> </u><u>centimeters</u><u>.</u>

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Brut [27]

Answer:

x⁵+ 45x⁴+ 810x³+ 7290x²+ 32805x +59049

Step-by-step explanation:

Greetings !

Given expression

(x + 9) {}^{5}

write 5 as a sum

(x + 9) {}^{3 + 2}

use \: a {}^{m + n}  = a {}^{m}  \times a {}^{n} to \: expand \: the \: expression.

(x + 9) {}^{3}  \times (x + 9) {}^{2}

Use (a+b)³=a³+3a²b+b³ to expand the expression

(x {}^{3}  + 27x {}^{2}  + 243x + 729) \times (x + 9) {}^{2}

Use (a+b)²=a²+2ab+b² to the second expression to expand it

(x {}^{3}  + 27x {}^{2}  + 243x + 729) \times(x {}^{2}  + 18x + 81)

Finally, simplify the expression gives

x {}^{5}  + 45x {}^{4}  + 810x {}^{3}  + 7290x {}^{2}  + 32805x + 59049

Hope it helps!

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What are the solutions of x2 - 2x +37 = 0 ?
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Answer:

See below ~

Step-by-step explanation:

<u>Given</u> : 3 angles of a Δ

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<u>Solving</u> :

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