Which one is the bigest and which one is the lowest 5 7/8 6 5.5 5 3/4

Mathematics

1 answer:

bulgar [2K]2 years ago

4 0

Answer:

Greatest to Least order: 6, 5 7/8, 5 3/4, 5.5

Step-by-step explanation:

First it's 6, then it's 5 7/8 because 5 7/8 = 5.875, then 5 3/4 because 5 3/4 = 5.75, and then 5.5 which is the lowest number.

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Readme [11.4K]

Answer:

Step-by-step explanation:

1. X=2

2. y = 8

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7 0

3 years ago

1. what is the perimeter of the triangle? 2. what is the area of the triangle?

jonny [76]

Answer:

See below. A=45 p=39.64

Step-by-step explanation:

Hi = 9 squares (h)

Gh= 14 squares. (b)

Area of a triangle = 1/2 bxh

1/2 14 x 9

7x9= 45.

Area =45 squares.

Perimiter

A= side hi (9)

B= side gh (14)

C= side gi (unknown)

A^2 + b^2 = c^2

9^2 + 14^2 = 277

C^2 = 277

Square root of 277 =c

C length =16.64 squares

A+b+c = perimeter

9+14+16.64 = 39.64 squares.

Sorry I cannot see the units of measure in the photo

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3 years ago

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Sergio039 [100]

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t$

now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)$

$\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)$