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irina [24]
2 years ago
5

In the system of equations below what is the value of y? 3x+3y=30 x=2y+1 (use substitute to solve.)

Mathematics
1 answer:
kolezko [41]2 years ago
4 0

Answer:

y= 3

Step-by-step explanation:

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Answer:

Hello,

First equation is false

Second equation is true

Step-by-step explanation:

1)

(4,-3) is a point of the line y=4x-19  since

-3=?4*4-19

-3=-3

2)

(4,-3) is not a point of the line y=1/4x-2 since

-3=? 1/4*4-2

-3=? 1-2

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I have written that because it is difficult for me to understand

"the negative reciprocal of the slope of the first"

the negative reciprocal of 4 should be -1/4.

Equation y=1/4x-2 is false.

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Answer: 126

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Use the table to determine the location with the greatest amount of rainfall and the location with the least amount of rainfall.
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Step-by-step explanation:

I think it is hilo hawii 480 cm it has the longest cm

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The price of a radio was $20 it's on sale for $15 what is the percent of change in the price of a radio
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26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
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