Answer:
D. 
Step-by-step explanation:
A square root can't be evaluated if the number we want to find the square of is nagative.
Answer:
Please see explanation for the answer. The code is written in python and is as given below:
Step-by-step explanation:
The solution is obtained on the Python with the following code
import matplotlib.pyplot as plotter
import numpy as npy
x_s = npy.linspace(-5,5,100) #Defining a linear sample space with boundaries as -5 to 5 and 100 as number of samples.
def sigmo(z):return 1/(1 + npy.exp(-z)) #Defining sigmoid function for the f(x).
plotter.plot(x_s, sigmo(x_s))
plotter.plot([-5,5],[.5,.5])
plotter.xlabel("z")
plotter.ylabel("sigmoid(z)")
plotter.show()
Answer:
where is the problem?
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
To figure out if (1,2) is a solution to the system, we can plug the values in and see if it is true.
3x-2y=-1
3(1)-2(2)=-1
3-4=-1
-1=-1
It is true for this equation. Now let's check the next one.
y=-x+3
2=-(1)+3
2=2
Since both equations are true when we plug the values in, (1,2) is a solution to the system.
Answer:
360
Step-by-step explanation: