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HACTEHA [7]
2 years ago
5

What is the value of x in the equation 2(x−3) 9=3(x 1) x? x = −3 x = −1 x = 0 x = 3

Mathematics
1 answer:
Masja [62]2 years ago
8 0

The solution of the linear equation is x = 0.

<h3>What is the linear equation?</h3>

An equation is a mathematical statement, which has an equal sign (=) between the algebraic expression.

Linear equations are the equations of degree 1.

The given linear equation is;

\rm 2(x-3)+ 9=3(x+ 1) +x

The value of x is determined in the following steps given below.\rm 2(x-3)+9=3(x+1)+x\\\\2x-6+9=3x+3+x\\\\\ 2x+3=4x+3\\\\3-3=4x-2x\\\\0=2x\\\\x=0

Hence, the solution of the linear equation is x = 0.

To know more about linear equations click the link given below.

brainly.com/question/5085290

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Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20

Compute the probability that a randomly selected component needs rework as follows:

P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069}  =0.3623

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

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3 years ago
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