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melomori [17]
3 years ago
8

How does the force of gravity on a raindrop compared with the air drag it encounters?

Physics
1 answer:
NISA [10]3 years ago
4 0
Because the drop is moving at constant velocity the net force acting on the raindrop is 0N. Therefore the force of gravity, say XN, pulling the drop downward is canceled out by the force of the air pressing onto the raindrop. So this force will be equal and opposite to the force of gravity, -XN.
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What is the relationship between the electric force and each one of the charges?
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For an object to be in static equilibrium, the net force must be equal to zero and and The center of gravity must be above the s
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4 years ago
A basketball player is 4.22 m from
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Answer: The height above the release point is 2.96 meters.

Explanation:

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P(t) = (9.20*cos(69°)*t, -4.9m/s^2*t^2 + 9.20m/s^2*sin(69°)*t)

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Now we evaluate the y-position in this time:

h =  -4.9m/s^2*(1.28s)^2 + 9.20m/s^2*sin(69°)*1.28s = 2.96m

The height above the release point is 2.96 meters.

3 0
3 years ago
Read 2 more answers
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Hope this helps!

3 0
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5.Insufficient Census Experts

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5 0
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