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3 years ago

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"The Mount Pinatubo Particle Model shows that the initial atmospheric flow of erupted fine ash and sulfur oxide was from _______

_. Subsequently, the prevailing westerlies dispersed the material to higher latitudes."

1 answer:

Leya [2.2K]3 years ago

6 0

Answer:

what

Explanation:

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What are political obstacles keeping wind turbine from being used?

erastova [34]

Explanation:

Turbines might cause noise and aesthetic pollution.

Although wind power plants have relatively little impact on the environment compared to conventional power plants, concern exists over the noise produced by the turbine blades and visual impacts to the landscape.

The inflexibility, variability, and relative unpredictability of wind power as a means for electricity production, are the most obvious barriers to an easy integration and widespread application of wind power." Thus, the uncertainty of the wind requires a system that is always available to replace all the electrical output created by the wind turbine system. In other words, it is too expensive to have wind turbines lying around that don't do anything.

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3 years ago

A 1000 kg weather rocket is launched straight up.The rocket motor provides a constant acceleration for 16 s, then the motor stop

Novay_Z [31]

Go with it hope this helps

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3 years ago

Hook's law describes an ideal spring. Many real springs are better described by the restoring force (FSp)s=−kΔs−q(Δs)^3, where q

kvasek [131]

Answer

given,

k = 250 N/m

q = 900 N/m³

(FSp)s=−kΔs−q(Δs)^3

work done = Force x displacement

$W = \int {F. dx}$

limits are x = 0 to x = 0.15 m

work done

$W = \int_0^{0.15} (k x + q x^3)\ dx$

$W = [\dfrac{kx^2}{2}+\dfrac{qx^4}{4}+ C]_0^0.15$

$W = \dfrac{300\times 0.15^2}{2}+\dfrac{900\times 0.15^4}{4}$

W = 3.375 + 0.1139

W = 3.3488 J

b) % cubic term = $\dfrac{0.1139}{3.3488}$

% cubic term = $3.4\ %$

7 0

3 years ago

As stream discharge increases ________. only velocity increases velocity, width, and depth increase velocity, width, and depth d

nignag [31]

As stream discharge increases, only velocity increases.

<h3>What is discharge?</h3>

The discharge or volume flow rate is defined as the product of the velocity of the fluid and the area of cross- section of the pipe or tube.

Discharge Q = Area A x Velocity V

Q = AV

The discharge is directly proportional to the velocity of the fluid. When discharge increases, velocity is the only physical quantity that can be changed.

Thus, As stream discharge increases, only velocity increases.

Learn more about discharge.

brainly.com/question/25727077

#SPJ1

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2 years ago

On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const

IceJOKER [234]

Answer:

a)

Explanation:

Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:

$x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2} (1)$

Since the car starts from rest, v₀ =0.
We know the value of t = 5 sec., but we need to find the value of a.
Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:

$a_{c} =\frac{v_{fc}}{t} = \frac{20m/s}{5s} = 4 m/s2 (2)$

Replacing a and t in (1):

$x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2} = \frac{1}{2}*a*t^{2} = \frac{1}{2}* 4 m/s2*(5s)^{2} = 50.0 m. (3)$

Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:

$a_{t} =\frac{-v_{to}}{t} = \frac{-20m/s}{10s} = -2 m/s2 (4)$

Replacing v₀, at and t in (1), we have:

$x_{ft} = 20m/s*10.0s + \frac{1}{2}*(-2 m/s2)*(10.0s)^{2} = 200m -100m = 100.0m (5)$

Therefore, as the truck travels twice as far as the car, the right answer is a).

7 0

3 years ago