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Ket [755]
2 years ago
6

Evaluate v(x)=12−2x−5 when x=−2,0, and 5.

Mathematics
1 answer:
olga_2 [115]2 years ago
3 0

Answer:

Step-by-step explanation:

v(x)=12-2x-5

v(-2)=12-2(-2)-5

      =11

v(0)=12-2(0)-5

     =7

v(5)=12-2(5)-5

     =-3

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\bf \textit{Periodic Exponential Decay}\\\\
A=I(1 - r)^{\frac{t}{p}}\qquad 
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A=\textit{accumulated amount}\to &1013\\
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\end{cases}
\\\\\\
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\bf \textit{Periodic Exponential Decay}\\\\
A=I(1- r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &1013\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &t\\
p=period\to &1000
\end{cases}
\\\\\\
A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.


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