<h2>
Answer with explanation:</h2>
Given : A standardized exam's scores are normally distributed.
Mean test score : 
Standard deviation : 
Let x be the random variable that represents the scores of students .
z-score : 
We know that generally , z-scores lower than -1.96 or higher than 1.96 are considered unusual .
For x= 1900
Since it lies between -1.96 and 1.96 , thus it is not unusual.
For x= 1240
Since it lies between -1.96 and 1.96 , thus it is not unusual.
For x= 2190
Since it is greater than 1.96 , thus it is unusual.
For x= 1240
Since it lies between -1.96 and 1.96 , thus it is not unusual.
Answer:
(x+6)(x−6)=0
x=-6 or x=6
Step-by-step explanation:
X^2 - 36 = 0
Solve by Square Root
add 36 both sides
x^2−36+36=0+36
x^2=36
square root
x=±√36
x=6 or x=−6
You can do that or for 2nd option
Solve by factoring
x^2-36=0
(x+6)(x−6)=0
Set factors equal to 0
x+6=0 or x−6=0
x=-6 or x=6
PLEASE NOTE: 36 is the square of 6
and
x2 is the square of x1
She could have taken the price and number of pounds and divided the price by two until she had the price for one of oranges. that is all i know, i hope it helps.
The function can be solved as follows:
- f(6 + 4) = 25
- f(6) - f(4) = 20
- f(6 - 4) = 1
- f(6) - f(4) = 6
- f(6) . f(4) = 91
<h3>How to solve function?</h3>
f(x) = 3x - 5
Therefore, the function can be solved as follows:
f(6 + 4) = f(10) = 3(10) - 5 = 25
f(6) + f(4) = 3(6) - 5 + (3(4) - 5)
f(6) - f(4) = 13 + 7
f(6) - f(4) = 20
f(6 - 4) = f(2) = 3(2) - 5 = 6 - 5 = 1
f(6) - f(4) = 3(6) - 5 - (3(4) - 5)
f(6) - f(4) = 18 - 5 - (12 - 5)
f(6) - f(4) = 13 - 7
f(6) - f(4) = 6
f(6.4) = f(24) = 3(24) - 5 = 72 - 5 = 67
f(6) . f(4) = (3(6) - 5 ) (3(4) - 5)
f(6) . f(4) = (18 - 5)(12 - 5)
f(6) . f(4) = (13)(7) = 91
learn more on function here: brainly.com/question/9390144
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