Answer:
C ≤ 2
Step-by-step explanation:
Given that :
Clayton is at most 2 meters above sea level ;
Let Clayton = C
Clayton's distance can be represented by the inequality :
2 meters above sea level is positive, +2
At most 2 meters above sea level means, Clayton could be anywhere between + 2 metwrs but not more than 2 meters
Hence, Clayton's distance can be represented by the inequality :
C ≤ 2
Answer:
2 whole pieces
5/24 feet left
Step-by-step explanation:
divide 5/6 by 5/16 = 2 2/3 pieces
so there are 2 whole pieces and 2/3 small piece.
The 2/3 small short equals to 5/16 x 2/3 = 5/24 ft
Answer: 20x^8 y^10
Step-by-step explanation:
First off, simplify the exponential of x and y and the integers on the left side of the equation getting 32x^8 y^10 - 12x^8 y^10 = 20x^8 y^10
It's quite simple. Look:
Lets let S- be the age of Sally and B- can be the age of Beth
S+B=60
S-6=3(B-6)
S-6=3B-18
S=3B-18+6
S=3B-12
3B-12+B=60
4B=60+12
4B=72
B=72/4
B=18
B=60-18
B=42
The ages are (B)18 and (S)42
Hope this helps!! :)
Time is 16.75 seconds when the arrow reaches 200 ft
Step-by-step explanation:
- Step 1: Find time at height of 200 ft
Height = 200 ft
v = 280 ft/s
Projectile formula, h = -16t² + vt
⇒ 200 = -16t² + 280t
⇒ 16t² - 280t + 200 = 0
⇒ 2t² - 35t + 25 = 0 (dividing by common factor 8)
Using quadratic formula to find t
t = (35 ±√35² - 4×2×25)/2×2
t = (35 ±√1225 - 200)4 = 35 ± 32.02/4
∴ t = 67/4 or 3/4
t = 16.75 seconds
