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KiRa [710]
2 years ago
15

Hi Guys I'm stuck on this question write x^2-4x+2 in the form (x-A)^2+B

Mathematics
2 answers:
Alexxx [7]2 years ago
8 0

Answer:

(x-2)² -2

Step-by-step explanation:

Consider that (a+b)² = a²+2ab+b²

To find the form (x-A)²+B compare  x²-4x+2 with a²+2ab+b²

x² - 4x +2

a² + 2 a b+ b², so a= x and b = (-2)

x²+ 2· x ·(-2)+ (-2)² -  2  = (x-2)² -2 is in the form (x-A)²+B

Check our answer:

(x-2)² -2= (x²-2·2x+4)-2 = x²-4x +2 ✅

MrRa [10]2 years ago
6 0

Answer:

(x-2)^2-2

Step-by-step explanation:

x^2-4x+2

take the x out

x(x-4) + 2

(x-2)^2-2

because (x-2)^2 is

x^2-4x+4

its like completing the square

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Answer if you know
Arlecino [84]
I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set y=1.25 for this example.)

The length of each cross section (the side lying in the base) has length determined by the horizontal distance x between the y-axis x=0 and the curve y=\sqrt x. In terms of y, this distance is x=y^2. The height of each cross section is twice the value of y, so the area of each rectangular cross section should be 2y^3.

This means the volume would be given by the integral

\displaystyle\int_0^22y^3\,\mathrm dy
8 0
3 years ago
Find the area of the shaded region. ​
densk [106]

[1]

A1 = (h (a + b)) / 2

A1 = (21 (17 + 32)) / 2

A1 = (21 x 49) / 2

A1 = 1,029 / 2

A1 = 514.5 mm²

[2]

A2 = (b x h) / 2

A2 = (11 x 9) / 2

A2 = 99 / 2

A2 = 49.5 mm²

[3]

The area of the shaded region =

A1 - A2 =

514.5 mm² - 49.5 mm² =

465 mm²

The answer is 465 mm².

4 0
3 years ago
The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of
Lunna [17]

Answer:

Change in area=24\pi-48

Step-by-step explanation:

Let s will be the side of square and r will be the radius of circle.

Then two given conditions are

1)dr/dt=2 m/s

2)ds/dt=1 m/s

Area enclosed=(Area of square)-(Area of circle)

Area of square=s^{2}

Area of circle=\pi r^{2}

Area enclosed=(\pi  r^{2})-s^{2}

dA/dt=2\pir(dr/dt)-2s(ds/dt)

At s=24,and r=6

dA/dt=2(\pi)(6)(2)-2(24)(1)

Change in area=24\pi-48

6 0
3 years ago
Solve this and please try to explain also​
olchik [2.2K]
It’s so easy 2*2=4 x=2
8 0
3 years ago
1. Rewrite the expression. Use an exponent, rather than repeated multiplication. (–4)(–4)
AlekseyPX
-4^2 is the same as -4*-4

-4*-4=16

-4^2= 16 

-4^2 is the exponent.

I hope this helps!
~kaikers
4 0
3 years ago
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