I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set

for this example.)
The length of each cross section (the side lying in the base) has length determined by the horizontal distance

between the y-axis

and the curve

. In terms of

, this distance is

. The height of each cross section is twice the value of

, so the area of each rectangular cross section should be

.
This means the volume would be given by the integral
[1]
A1 = (h (a + b)) / 2
A1 = (21 (17 + 32)) / 2
A1 = (21 x 49) / 2
A1 = 1,029 / 2
A1 = 514.5 mm²
[2]
A2 = (b x h) / 2
A2 = (11 x 9) / 2
A2 = 99 / 2
A2 = 49.5 mm²
[3]
The area of the shaded region =
A1 - A2 =
514.5 mm² - 49.5 mm² =
465 mm²
The answer is 465 mm².
Answer:
Change in area=24
-48
Step-by-step explanation:
Let s will be the side of square and r will be the radius of circle.
Then two given conditions are
1)dr/dt=2 m/s
2)ds/dt=1 m/s
Area enclosed=(Area of square)-(Area of circle)
Area of square=
Area of circle=
Area enclosed=
dA/dt=2
r(dr/dt)-2s(ds/dt)
At s=24,and r=6
dA/dt=2(
)(6)(2)-2(24)(1)
Change in area=24
-48
-4^2 is the same as -4*-4
-4*-4=16
-4^2= 16
-4^2 is the exponent.
I hope this helps!
~kaikers