The answer is a I believe
I hope this helped :)
Answer:
yes
Step-by-step explanation:
Answer:
y = (3/2)x + 8
Step-by-step explanation:
Hi
First let's find the slope of the given line by converting to slope-intercept form:-
2x + 3y = 9
3y = -2x + 9
y = (-2/3)x + 3
From this we see that the slope is -2/3.
The slope of a line perpendicular to this one will be - 1 / (-2/3)
= 3/2. ( because for a line and its perpendicular, the slopes' product = -1).
Using the point-slope form to find the equation of this line
y - y1 = m(x - x1). Here m = slope and (x1, y1) is a point on the line.
Plugging in the given values , m = 3/2 , x1 = -2 and y1 = 5:-
y - 5 = 3/2 (x - -2)
y - 5 = 3/2x + 3
y = (3/2)x + 8 which is the equation in slope-intercept form.
Step-by-step explanation:
The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:
let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9
let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9
let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9
let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9
let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9
let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9
You can continue to increase the length of the square and follow this pattern and it will be consistent.
