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Andru [333]
3 years ago
8

Walt's Marina generated the following regression based on the number and cost of daily rentals of its boat slips to boat owners

each month.
SUMMARY OUTPUT
Regression Statistics
Multiple R 0.425358
R Square 0.481216
Adj RSquare 0.456695
Stand. Error 39.35892
Observations
ANOVA Sig
df SS MS F sig F
Regression 1 43,034.7 43,034.71 0.000151
Residual 13 20,138.6 1,549.12
Total 14 63,173.3
MS Full 27.780017 | 14 Intercept X Variable 1
Coefficients Std Error t Stat P-value Lower Upper Lower Upper
95% 95% 95% 95%
Intercept 2621.21101.8073 2.626725 0.020917 47.478460 487.3612 47.478460 X variable 35.58 6.1023 5.270675 0.000151 18.980154 45.3467 18.980154
Walt's Marina rents 45 boat slips each month (within relevant range), how much is its total cost for boat slip rentals?
A. $4,222
B. $8,722
C. $4,581
D. Not available based on the information
Which one of the following is a purely fixed cost?
1000 units 2000 units
Total Per Unit Total Per Unit
Cost A 500 0.2 1000 0.2
Cost B 2000 5 2000 2.5
Cost C 750 3.2 1000 2.4
Cost D 100 0.5 250 0.3
A. Cost A
B. Cost B
C. Cost C
D. Cost D
Mathematics
1 answer:
Lana71 [14]3 years ago
5 0

Answer:

The answer is "Option A and Option B"

Step-by-step explanation:

In question 1:

The fixed cost=2621.21  

The unit variable cost=35.58  

Calculating the total cost for 45 boat slips:

=2621.21+(45 \times 35.58)\\\\=2621.21+(1601.1)\\\\=4222.31 \approx 4222

In question 2:

It is the pure fixed costs that remain consistent in total regardless of dynamic loads. An overall cost B both for 1000 and 2000 unit is unchanged, therefore the Cost B is a fixed sum.

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According to the rational root theorem, what are all the potential rational roots of f(x)= 5x^3-7x+11
Tems11 [23]

The rational root theorem states that the rational roots of a polynomial can only be in the form p/q, where p divides the constant term, and q divides the leading term.

In your case, both the leading term 5 and the constant term 11 are primes, so their only divisors are 1 and themselves.

So, the only feasible solutions are

\pm\dfrac{11}{5},\quad\pm 11,\quad \pm\dfrac{1}{5}, \pm 1

For the record, in this case, none of the feasible solutions are actually a root of the polynomial.

8 0
3 years ago
How many lb of brand X sugar which
Dafna1 [17]

Answer:  <u>4 pounds</u> of brand X sugar

====================================================

Reason:

n = number of pounds of brand X sugar

5n = cost of buying those n pounds, at $5 per pound

Brand Y costs $2 per pound, and you buy 8 lbs of it, so that's another 2*8 = 16 dollars.

5n+16 = total cost of brand X and brand Y combined

n+8 = total amount of sugar bought, in pounds

3(n+8) = total cost because we buy n+8 pounds at $3 per pound

The 5n+16 and 3(n+8) represent the same total cost.

Set them equal to each other. Solve for n.

5n+16 = 3(n+8)

5n+16 = 3n+24

5n-3n = 24-16

2n = 8

n = 8/2

n = 4 pounds of brand X sugar are needed

-------------

Check:

n = 4

5n = 5*4 = 20 dollars spent on brand X alone

16 dollars spent on brand Y mentioned earlier

20+16 = 36 dollars spent total

n+8 = 4+8 = 12 pounds of both types of sugar brands combined

3*12 = 36 dollars spent on both types of sugar brands

The answer is confirmed.

--------------

Another way to verify:

5n+16 = 3(n+8)

5*4+16 = 3(4+8)

20+16 = 3(12)

36 = 36

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2 years ago
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Answer:

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Step-by-step explanation:

This system of equations has no solution because when graphed, the lines are parallel to each other. Meaning they will never intersect. Since they will never intersect, there are no solutions.

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kap26 [50]

Answer:

A

Step-by-step explanation:

Given

x² - x = 30

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- \frac{1}{2})x + \frac{1}{4} = 30 + \frac{1}{4}

(x - \frac{1}{2})² = \frac{121}{4}

Take the square root of both sides

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Add \frac{1}{2} to both sides

x = \frac{1}{2} ± \frac{11}{2}, thus

x = \frac{1}{2} - \frac{11}{2} = - 5

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