Question

Q2 (i). A line “t” is parallel to 3y = 6x + 9. Find the slope of this line “t”. (ii) Another line “r” is perpendicular to the line 3y = 6x + 9. Find the gradient of the line “r”. plz can anyone tell me by doing the practice on the copy I will be thankful

Answer 1

Answer: 6 and -1/6

Step-by-step explanation:

solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6.

Answer 2

Answer:

1) 2

2) -1/2

Step-by-step explanation:

1) 3y= 6x+9

y= 2x+3

Slope is 2

Parallel line "t" has the same slope, it will have equation:

y= 2x+b

2) y =2x+3

Perpendicular line"r" has a slope opposite-reciprocal to this, so the slope will be -1/2, the equation for line"r" is:

y= -1/2x +b

The gradient of the line is same as slope and it is -1/2 for line"r"