<span>it depends how the interest is calculated, but there's not much of a difference
assuming its continuously compouned, you use this formula: A(t)=Pe^(rt), where A is the final amount, P is the initial investment, r is the interest, and t is the time in years
you want to find t such that A(t)=18,600 so 18,600=1000e^(.0675t)
you need to use logarithm to figure it out, take the natural log of both sides
the following properties will come into use:
ln(a*b)=ln(a)+ln(b)
ln(a^b)=bln(a)
ln(e)=1
taking the natural log
ln(18,600)=ln(1000e^(.0675t))
ln(18,600)=ln(1000)+ln(e^.0675t)
ln(18600)=ln(1000) + .0675t
now solve for t: t= (ln(18600)-ln(1000))/.0675
t=43.31</span>
Answer:
4/(√7 + √3)
Step-by-step explanation:
=> Multiply and divide by (√7-√3)
=> 4(√7 - √3)/((√7 + √3)(√7 - √3)
=> 4(√7 - √3)/((√7)² - (√3)²)
=> 4(√7 - √3)/((7) - (3))
=> 4(√7 - √3)/4
=> √7 - √3
Answer: 4 games
Step-by-step explanation:
Whether Denise bowls or not, he incurs rent for bowling shoes and per bowling he has to pay $4.75 while he rented shoes for $3.
Then the equation is:
y = 3 + 4.75x
Where
y is the total cost
x is Number of bowling
y = 3 + 4.75x
3 + 4.75x = 22
4.75x = 22 - 3
4.75x = 19
x = 19/4.75
x = 4
Denise bowled 4 games.
Evaluate 10 m +\frac {n^2}410m+ 4 n 2 10, m, plus, start fraction, n, start superscript, 2, end superscript, divided by, 4, en
DerKrebs [107]
Evaluate the expression 
where m=5 and n=4
We replace the value of m and n to evaluate
m=5 and n=4
50 + 4 = 54
The value of the given expression is 54 when m=5 and n= 4
