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3 years ago

HELP!! WILL GIVE BRAINLIST!!

Mathematics

2 answers:

Sphinxa [80]3 years ago

8 0

That is what I found

sergij07 [2.7K]3 years ago

4 0

Answer:

$str + stu = 180 \\ 180 - 20 = 4x \\ 160 = 4x \\ x = 40$

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What are the solutions of 2x^2+3x-7=x^2+5x+39

sveticcg [70]

Answer:

${x}^{2} - 2x - 46$

Step-by-step explanation:

${2x}^{2} + 3x - 7 = {x}^{2} + 5x + 39$

Collect like terms

${2x }^{2} - {x}^{2} + 3x - 5x - 7 - 39$

${ x}^{2} - 2x - 46$

7 0

4 years ago

Hi people if someone gives me a hint please. Show algebraically that the product of two consecutive numbers is always even l wro

Andru [333]

Step-by-step explanation:

Consider the following rules.

even + odd = odd

even - odd = odd

even × odd = even

even ÷ odd = even (if divisible)

Now for the two consectives terms...

One will surely be even and the other, odd.

So using the rule

Their product will always be odd

Hope it helps....

BRAINLIEST PRETTY PLEASE!!

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4 years ago

2x-4y+7=0 how do I find the slope for this?

Digiron [165]

Answer:

The slope is 1/2 and the y intercept is 7/4

Step-by-step explanation:

2x-4y+7=0

To find the slope, we need to put the equation in slope intercept form

y = mx+b

So we need to solve for y

Subtract 2x from each side

2x-2x-4y+7=0-2x

-4y +7 = -2x

Subtract -7

-4y+7-7 = -2x-7

-4y = -2x-7

Divide by -4

-4y/-4 = -2x/-4 -7/-4

y = 1/2 x +7/4

The slope is 1/2 and the y intercept is 7/4

8 0

3 years ago

Suppose scores on exams in statistics are normally distributed with an unknown population mean and a population standard deviati

Anna71 [15]

Answer:

( 67.18, 68.82)

Step-by-step explanation:

Let $\mu$ be the true (population) mean of statistics exam scores. We have a large random sample of n = 36 scores with a sample mean (sample mean score) of $\bar{x} = 68$ . We know that the population standard deviation is $\sigma = 3$ . A pivotal quantity is $(\bar{x}-\mu)/(3/\sqrt{36}) = (\bar{x}-\mu)/(3/6) = (68-\mu)/(1/2)$ which is approximately normally distributed and $P(-z_{0.05}\leq(68-\mu)/(1/2)\leq z_{0.05}) = 0.90$ where $-z_{0.05} =-1.6449$ , and so, $P(-1.6449\leq(68-\mu)/(1/2)\leq 1.6449) = 0.90$ . Therefore the 90% confidence interval is (68-(1/2)(1.6449), 68+(1/2)(1.6449)), i.e., ( 67.18, 68.82)

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3 years ago

Sally had seventy - seven dollars to spend on eight books. After buying them she had thirteen dollars. How much did each book co

4vir4ik [10]

8 books because 77 minus 13 is 64. 64 divided by 8 is 8.

6 0

3 years ago