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3 years ago

12

dee dee bought an apple for $0.85, a sandwich for $4.50, and a bottle of water for $1.50. how much did dee dee spend?

2 answers:

LenaWriter [7]3 years ago

4 0

All you need to do is add these up. Get rid of the $ symbols, the fact that it's money doesn't play a part in the calculation.

0.85 + 4.50 + 1.50 = 6.85

An easy way to make this easier is to add the part before the decimal place first so 4 + 1 = 5. Then add 0.5 + 0.5 that makes 1. So you have 6. Now you just have 0.85 left. So the answer is 6.85.

Zinaida [17]3 years ago

3 0

0.85+4.50+1.50=6.85. $6.85

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3 years ago

Gisele trains 7 days per week for a biathlon. She covers a total of 20 miles cycling and running each day. Gisele cycles a total

IgorLugansk [536]

The choice which describes the solution is; The solution is 5, which represents the number of miles she runs each day.

<h3>Word problems</h3>

According to the task content;

The total distance covered running and cycling per day is; 20miles

Additionally, she cycles a total of 105 miles each week.

From the statement above; it follows that;

The number of miles she cycles per day since 7 days make a week is;

105/7 = 15.

Hence, it follows that the equation; (15+r) = 20 represents the daily distance covered by cycling and running.

On this note, it follows that;

r = 20 -15 = 5.

Hence, The solution is 5, which represents the number of miles she runs each day.

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2 years ago

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3 years ago

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Let $v$ be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

$\begin{cases}s_A(t) = vt\\s_B(t) = -\dfrac{8}{7}vt+450\end{cases}$

where $s_A,\ s_B$ are the positions of trains A and B respectively, and t is the time in hours.

The two trains meet if and only if $s_A=s_B$ , and we know that this happens after two hours, i.e. at $t=2$

$\begin{cases}s_A(2) = 2v\\s_B(2) = -\dfrac{16}{7}v+450\end{cases}\implies 2v = -\dfrac{16}{7}v+450$

Solving this equation for v we have

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So, train A is travelling at 105 km/h. This implies that train B travels at

$105\cdot \dfrac{8}{7} = 15\cdot 8=120 \text{ km/h}$

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anyanavicka [17]

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