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Afina-wow [57]
2 years ago
6

The figure above shows a rod that is fixed to a horizontal surface at pivot P The rod is initially rotating

Physics
1 answer:
Lisa [10]2 years ago
5 0

The angular speed is decreasing and direction of rotation clockwise of the rod immediately after time t.

<h3></h3><h3>What is angular speed ?</h3>

The rate of change of angular displacement is defined as angular speed.  It is stated as follows:

ω = θ t

Where,

θ is the angle of rotation,

t is the time

ω is the angular velocity

The torque is found as;l

\rm  T = F \times r

If the force is acting on the rod  from the three point is the same, the value of the torque is depends upon the radius or the perpendicular distance.

The perpendicular distance of the right force is grater. Hence, the force acting on the right side is more, and the rod will rotate clockwise.

Both the forces are acting downwards. Thus, the resultant force is the less due to which the speed is increasing.

Hence, the angular speed is decreasing and direction of rotation clockwise of the rod immediately after time t.

To learn more about the angular speed, refer to the link;

brainly.com/question/9684874

#SPJ1

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physics A river flows at a speed vr = 5.37 km/hr with respect to the shoreline. A boat needs to go perpendicular to the shorelin
vova2212 [387]

Answer: Vb is the vector  (-5.37m/s,  8.59 m/s), with a module 10.13m/s

then the ratio Vb/Vr = 10.13m/s/5.37m/s = 1.9

Explanation:

We can use the notation (x, y) where the river flows in the x-axis and the pier is on the y-axis.

We have Vr = (5.37m/s, 0m/s)

Now, if the boat wants to move only along the y-axis (perpendicularly to the shore).

The velocity of the boat Vb will be:

Vb = (-c*sin(32). c*cos(32))

Then we should have that:

5.37 m/s - c*sin(32) = 0

c = (5.37/sin(32))m/s = 10.13 m/s

the velocity in the y-axis is:

10.13m/s*cos(32) = 8.59 m/s

So Vb = (-5.37m/s,  8.59 m/s)

the ratio Vb/Vr = 10.13m/s/5.37m/s = 1.9 where i used Vb as the module of the boat's velocity.

7 0
3 years ago
Please help me !! Thank you
ira [324]
I think it would be Fusing of 2 or more small atoms into a larger one
4 0
3 years ago
Read 2 more answers
An event occurs in system K' at x' = 2 m, y' = 3.7 m, z' = 3.7 m, and t' = 0. System K' and K have their axes coincident at t =
fiasKO [112]

Answer:

Coordinates of event in system K are (x,y,z,t)=(5.103m , 3.7m , 3.7m , 1.57×10⁻⁸s)

Explanation:

To find the coordinates of event in system K ,we have to use inverse Lorentz transformation

So

x=\frac{x^{|}+vt^{|} }{\sqrt{1-\frac{v^{2} }{c{2} } } } \\x=\frac{2m+0.92c(0) }{\sqrt{1-\frac{(0.92c)^{2} }{c{2} } } }\\x=5.103m\\y=y^{|}\\ y=3.7m\\z=z^{|}\\ z=3.7m

for t

r=\frac{1}{\sqrt{1-v^{2} } } \\r=\frac{1}{\sqrt{1-(0.92)^{2} } } \\r=2.551\\t=r(t^{|}+vx^{|}/c^{2}   )\\t=2.551(0s+(0.92c)(2)/c^{2} )\\t=1.57*10^{-8}s

Coordinates of event in system K are (x,y,z,t)=(5.103m , 3.7m , 3.7m , 1.57×10⁻⁸s)

6 0
3 years ago
Lighting a match changes chemical energy into heat and light. The total amount of energy _____.
Mariulka [41]
Hello.

The answer is <span>remains the same.

</span>The total amount of energy stays the same because the 1st Law of Thermodynamics states that energy can neither be created nor destroyed, it can only change forms. <span>So the chemical energy is just being converted into heat and light.
</span>
Have a nice day
8 0
3 years ago
Read 2 more answers
Sherry and Ellen are talking about the factors that affect light scattering in the atmosphere. Sherry says one factor is the len
Delvig [45]

Sherry who says one factor is the length of the path of sunlight is correct.

<h3>Factors affecting light scattering</h3>

There are two main factors which affects light scattering, and they include the following;

  1. the size of the particles
  2. wavelength of the light

length of the path of sunlight is equivalent to wavelength of the light.

Thus, we can conclude that Sherry who says one factor is the length of the path of sunlight is correct.

Learn more about light scattering here: brainly.com/question/1381101

#SPJ1

3 0
2 years ago
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