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Norma-Jean [14]
3 years ago
10

A race car enters the circular portion of a track that has a radius of 69 m. When the car enters the curve at point P, it is tra

veling with a speed of 120 km/h that is increasing at 5 m/s2. Three seconds later, determine the x and y components of velocity and acceleration of the car.
Physics
1 answer:
Masja [62]3 years ago
3 0

Photo Answer:

check the photo

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A 30 N rightward force is exerted on a 7 kg object. There is a 3 N force of friction acting on the object. What is the Weight of
IgorLugansk [536]

Answer:

W = 68.6 N

Explanation:

Given that,

Force acting on a right side = 30 N

Mass of the object, m = 7 kg

The force of friction acting on the car = 3 N

We need to find the weight of the object.

The weight of an object is given by :

W = mg

Substitute all the values,

W = 7 × 9.8

W = 68.6 N

So, the weight of the object is 68.6 N.

6 0
3 years ago
Is Experience Nature or Nurture
Stella [2.4K]

Answer:

Nature

Explanation:

6 0
4 years ago
Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.
boyakko [2]

Answer:

71.0 \mu m

Explanation:

The formula for the single-slit diffraction is

y=\frac{n\lambda D}{d}

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light

In this problem,

\lambda=648.0 nm=6.48\cdot 10^{-7}m

D=57.5 cm=0.575 m

y=1.05 cm=0.0105 m, with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m

6 0
3 years ago
Anuja is holding a stuffed dog, with a mass of 0.30 kg, when Derek decides that he wants it and tries to pull it away from Abuja
igor_vitrenko [27]

Answer:

a = 3.33 m/s²

Explanation:

The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:

F = ma

where,

F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N

m = mass of the dog = 0.3 kg

a = horizontal acceleration of dog = ?

Therefore,

1 N = 0.3 kg(a)

a = 1 N/0.3 kg

<u>a = 3.33 m/s²</u>

8 0
3 years ago
It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°C. The specific heat of the substance is 1.2
Akimi4 [234]
I'll assume you are looking for the mass of the object, since that is the missing piece of the puzzle.

The important equation for heat and energy is

Energy = mass × specific heat × change in temperature

Things we know:
Energy needed is 350 J.
Specific heat = 1.2 J/g°C
Temp. change = (30-20)°

Now we just need to plug those in and rearrange the formula to find the mass!

350 = mass × 1.2 × 10
6 0
4 years ago
Read 2 more answers
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