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3 years ago

9

On power line,birds can enjoy sitting from one live wire to the other.Howeber,if a person touches it,then the person will die wi

thin split seconds.Explain this situation

1 answer:

Fantom [35]3 years ago

7 0

Answer:

Because when birds sit on the electeic wire it prevents earthing of the birds with the ground and thus they doesn't get an electeic shock...

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Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the

Lilit [14]

Answer:

Explanation:

The force of friction acting on the system

= .04 x 9.8 ( 10.2 + 7 )

= 6.74 N

Net force = 8.9 - 6.74

= 2.16 N

Acceleration in the system

= 2.16 / ( 10.2 + 7 )

= .12558 m / s ²

Contact force between boxes = FP

Considering force on box A

Net force = 8.9 - FP

Applying Newton's law on box A

8.9 - FP = 10.2 x .12558

= 1.28

FP = 8.9 - 1.28

= 7.62 N

5 0

3 years ago

What is 3600Hz has in rpm?

Setler [38]

Answer:

Explanation:

N=Rotor Speed in Revolution per minute(rpm)

for P=4 and N=3600, f comes out to be 120 Hz.

So frequency of voltage produced is 120 Hz. But this is not practical. Generally 4-Pole generator has N=1500rpm(for 50 Hz) or 1800rpm for 60 Hz. Two pole generator can have N=3600rpm(f=60Hz).

The most practical situation is generator having N=3600Hz with 2 Poles.

Hope It will be helpful!!!

8 0

3 years ago

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approxim

Schach [20]

Complete Question

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 30.5 m/s (about 68 mph ) around the turn.

Required:

a. What is the race car's centripetal (radial) acceleration?

b. What is the force responsible for the centripetal acceleration in this case?

O normal

O gravity

O friction

O weight

Answer:

question a

$a = 16.32 \ m/s^2$

question b

correct option is option 3

Explanation:

From the question we are told that

The radius is $r = 57.0 \ m \$

The constant speed at which the race car is travelling is $v = 30 .5 \ m/s$

Generally from the question we are told that the track is completely flat so the only force pulling the car to the middle is the frictional force hence the centripetal force is due to the frictional force

Generally the centripetal acceleration is mathematically represented as

$a = \frac{v^2}{r}$

=> $a = \frac{30.5^2}{ 57}$

=> $a = 16.32 \ m/s^2$

6 0

3 years ago

How do you measure loudness?

BlackZzzverrR [31]

I think the correct question would be, how do you measure sound. :)
you measure sound by using amplitude. It measures how forceful the sound is.
Thats how you know whether its loud or quite :)
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5 0

4 years ago

Read 2 more answers

A basketball player shoots toward a basket 4.9 m away and 3.0 m above the floor. If the ball is released 1.8 m above the floor a

Zolol [24]

Answer:

v₀ = 6.64 m / s

Explanation:

This is a projectile throwing exercise

x = v₀ₓ t

y = y₀ + v_{oy} t - ½ g t²

In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m

the time to reach the basket is

t = x / v₀ₓ

we substitute

y- y₀ = $\frac{ v_o \ x \ sin \theta }{ v_o \ cos \theta} - \frac{1}{2} g \ \frac{x^2 }{v_o^2 \ cos^2 \theta }$

y - y₀ = x tan θ - $\frac{ g \ x^2 }{ 2 \ cos^2 \theta } \ \frac{1}{v_o^2 }$

we substitute the values

3 -1.8 = 3.0 tan 60 - $\frac{ 9.8 \ 3^2 }{2 \ cos^2 60 } \ \frac{1}{v_o^2}$

1.2 = 5.196 - 176.4 1 / v₀²

176.4 1 / v₀² = 3.996

v₀ = $\sqrt{ \frac{ 176.4}{3.996} }$

v₀ = 6.64 m / s

6 0

3 years ago